YES(?,O(n^1))
0.16/0.24	YES(?,O(n^1))
0.16/0.25	
0.16/0.25	Problem:
0.16/0.25	 filter(cons(X),0(),M) -> cons(0())
0.16/0.25	 filter(cons(X),s(N),M) -> cons(X)
0.16/0.25	 sieve(cons(0())) -> cons(0())
0.16/0.25	 sieve(cons(s(N))) -> cons(s(N))
0.16/0.25	 nats(N) -> cons(N)
0.16/0.25	 zprimes() -> sieve(nats(s(s(0()))))
0.16/0.25	
0.16/0.25	Proof:
0.16/0.25	 Bounds Processor:
0.16/0.25	  bound: 2
0.16/0.25	  enrichment: match
0.16/0.25	  automaton:
0.16/0.25	   final states: {7,6,5,4}
0.16/0.25	   transitions:
0.16/0.25	    sieve1(12) -> 7*
0.16/0.25	    nats1(11) -> 12*
0.16/0.25	    s1(10) -> 11*
0.16/0.25	    s1(2) -> 9*
0.16/0.25	    s1(9) -> 10*
0.16/0.25	    s1(1) -> 9*
0.16/0.25	    s1(3) -> 9*
0.16/0.25	    01() -> 9*
0.16/0.25	    cons1(2) -> 6,4
0.16/0.25	    cons1(9) -> 5,4
0.16/0.25	    cons1(1) -> 6,4
0.16/0.25	    cons1(3) -> 6,4
0.16/0.25	    cons2(16) -> 7*
0.16/0.25	    cons2(11) -> 12*
0.16/0.25	    s2(10) -> 16*
0.16/0.25	    filter0(1,1,1) -> 4*
0.16/0.25	    filter0(1,3,1) -> 4*
0.16/0.25	    filter0(1,2,3) -> 4*
0.16/0.25	    filter0(2,2,1) -> 4*
0.16/0.25	    filter0(2,1,3) -> 4*
0.16/0.25	    filter0(2,3,3) -> 4*
0.16/0.25	    filter0(3,1,1) -> 4*
0.16/0.25	    filter0(1,1,2) -> 4*
0.16/0.25	    filter0(3,3,1) -> 4*
0.16/0.25	    filter0(1,3,2) -> 4*
0.16/0.25	    filter0(3,2,3) -> 4*
0.16/0.25	    filter0(2,2,2) -> 4*
0.16/0.25	    filter0(3,1,2) -> 4*
0.16/0.25	    filter0(3,3,2) -> 4*
0.16/0.25	    filter0(1,2,1) -> 4*
0.16/0.25	    filter0(1,1,3) -> 4*
0.16/0.25	    filter0(1,3,3) -> 4*
0.16/0.25	    filter0(2,1,1) -> 4*
0.16/0.25	    filter0(2,3,1) -> 4*
0.16/0.25	    filter0(2,2,3) -> 4*
0.16/0.25	    filter0(3,2,1) -> 4*
0.16/0.25	    filter0(1,2,2) -> 4*
0.16/0.25	    filter0(3,1,3) -> 4*
0.16/0.25	    filter0(3,3,3) -> 4*
0.16/0.25	    filter0(2,1,2) -> 4*
0.16/0.25	    filter0(2,3,2) -> 4*
0.16/0.25	    filter0(3,2,2) -> 4*
0.16/0.25	    cons0(2) -> 1*
0.16/0.25	    cons0(1) -> 1*
0.16/0.25	    cons0(3) -> 1*
0.16/0.25	    00() -> 2*
0.16/0.25	    s0(2) -> 3*
0.16/0.25	    s0(1) -> 3*
0.16/0.25	    s0(3) -> 3*
0.16/0.25	    sieve0(2) -> 5*
0.16/0.25	    sieve0(1) -> 5*
0.16/0.25	    sieve0(3) -> 5*
0.16/0.25	    nats0(2) -> 6*
0.16/0.25	    nats0(1) -> 6*
0.16/0.25	    nats0(3) -> 6*
0.16/0.25	    zprimes0() -> 7*
0.16/0.25	  problem:
0.16/0.25	   
0.16/0.25	  Qed
0.16/0.25	EOF