The rewrite relation of the following conditional TRS is considered.
eq(0,0) | → | true | |
eq(s(x),0) | → | false | |
eq(0,s(y)) | → | false | |
eq(s(x),s(y)) | → | eq(x,y) | |
lte(0,y) | → | true | |
lte(s(x),0) | → | false | |
lte(s(x),s(y)) | → | lte(x,y) | |
m(0,s(y)) | → | 0 | |
m(x,0) | → | x | |
m(s(x),s(y)) | → | m(x,y) | |
mod(0,y) | → | 0 | |
mod(s(x),0) | → | 0 | |
mod(s(x),s(y)) | → | mod(m(x,y),s(y)) | | lte(y,x) ≈ true |
mod(s(x),s(y)) | → | s(x) | | lte(y,x) ≈ false |
filter(n,r,nil) | → | nil | |
filter(n,r,cons(x,xs)) | → | cons(x,filter(n,r,xs)) | | mod(x,n) ≈ r', eq(r,r') ≈ true |
filter(n,r,cons(x,xs)) | → | filter(n,r,xs) | | mod(x,n) ≈ r', eq(r,r') ≈ false |
eq(0,0) | → | true | |
eq(s(x),0) | → | false | |
eq(0,s(y)) | → | false | |
eq(s(x),s(y)) | → | eq(x,y) | |
lte(0,y) | → | true | |
lte(s(x),0) | → | false | |
lte(s(x),s(y)) | → | lte(x,y) | |
m(0,s(y)) | → | 0 | |
m(x,0) | → | x | |
m(s(x),s(y)) | → | m(x,y) | |
mod(0,y) | → | 0 | |
mod(s(x),0) | → | 0 | |
mod(s(x),s(y)) | → | mod(m(x,y),s(y)) | | lte(y,x) ≈ true |
mod(s(x),s(y)) | → | s(x) | | lte(y,x) ≈ false |
filter(n,r,nil) | → | nil | |
filter(n,r,cons(x,xs)) | → | cons(x,filter(n,r,xs)) | | eq(r,mod(x,n)) ≈ true |
filter(n,r,cons(x,xs)) | → | filter(n,r,xs) | | eq(r,mod(x,n)) ≈ false |