Certification Problem
Input (COPS 684)
We consider the TRS containing the following rules:
b |
→ |
c |
(1) |
b |
→ |
f(c) |
(2) |
c |
→ |
c |
(3) |
The underlying signature is as follows:
{b/0, c/0, f/1}Property / Task
Prove or disprove confluence.Answer / Result
No.Proof (by csi @ CoCo 2020)
1 Non-Joinable Fork
The system is not confluent due to the following forking derivations.
The two resulting terms cannot be joined for the following reason:
-
The reachable terms of these two terms are approximated via the following two tree automata,
and the tree automata have an empty intersection.
-
Automaton 1
-
final states:
{1}
-
transitions:
The automaton is closed under rewriting as it is compatible.
-
Automaton 2
-
final states:
{3}
-
transitions:
The automaton is closed under rewriting as it is compatible.