Certification Problem
Input (COPS 510)
We consider the TRS containing the following rules:
a |
→ |
a |
(1) |
f(b,x) |
→ |
b |
(2) |
f(x,a) |
→ |
a |
(3) |
The underlying signature is as follows:
{a/0, f/2, b/0}Property / Task
Prove or disprove confluence.Answer / Result
No.Proof (by csi @ CoCo 2020)
1 Non-Joinable Fork
The system is not confluent due to the following forking derivations.
The two resulting terms cannot be joined for the following reason:
-
The reachable terms of these two terms are approximated via the following two tree automata,
and the tree automata have an empty intersection.
-
Automaton 1
-
final states:
{1}
-
transitions:
The automaton is closed under rewriting as it is compatible.
-
Automaton 2
-
final states:
{2}
-
transitions:
The automaton is closed under rewriting as it is compatible.