We consider the TRS containing the following rules:
-(0,0) | → | 0 | (1) |
-(s(x),0) | → | s(x) | (2) |
-(x,s(y)) | → | -(d(x),y) | (3) |
d(s(x)) | → | x | (4) |
-(s(x),s(y)) | → | -(x,y) | (5) |
-(d(x),y) | → | -(x,s(y)) | (6) |
The underlying signature is as follows:
{-/2, 0/0, s/1, d/1}To prove that the TRS is (non-)confluent, we show (non-)confluence of the following modified system:
-(d(x),y) | → | -(x,s(y)) | (6) |
-(s(x),s(y)) | → | -(x,y) | (5) |
d(s(x)) | → | x | (4) |
-(x,s(y)) | → | -(d(x),y) | (3) |
-(s(x),0) | → | s(x) | (2) |
-(0,0) | → | 0 | (1) |
-(d(x),y) | → | -(d(x),y) | (7) |
-(x,s(y)) | → | -(x,s(y)) | (8) |
All redundant rules that were added or removed can be simulated in 2 steps .