We consider the TRS containing the following rules:
f(f(x)) | → | f(g(f(x))) | (1) |
The underlying signature is as follows:
{f/1, g/1}To prove that the TRS is (non-)confluent, we show (non-)confluence of the following modified system:
f(f(x)) | → | f(g(f(x))) | (1) |
All redundant rules that were added or removed can be simulated in 2 steps .