Certification Problem
Input (COPS 953)
We consider the TRS containing the following rules:
a(a(x)) |
→ |
a(b(a(x))) |
(1) |
b(a(b(x))) |
→ |
a(c(a(x))) |
(2) |
The underlying signature is as follows:
{a/1, b/1, c/1}Property / Task
Prove or disprove confluence.Answer / Result
Yes.Proof (by csi @ CoCo 2022)
1 Decreasing Diagrams
1.2 Rule Labeling
Confluence is proven, because all critical peaks can be joined decreasingly
using the following rule labeling function (rules that are not shown have label 0).
-
↦ 0
-
b(a(b(x))) |
→ |
a(c(a(x))) |
(2) |
↦ 2
The critical pairs can be joined as follows. Here,
↔ is always chosen as an appropriate rewrite relation which
is automatically inferred by the certifier.
-
The critical peak s = a(a(b(a(x11))))←→ε a(b(a(a(x11)))) = t can be joined as follows.
s
↔ a(b(a(b(a(x11))))) ↔
t
-
The critical peak s = b(a(a(c(a(x12)))))←→ε a(c(a(a(b(x12))))) = t can be joined as follows.
s
↔ b(a(b(a(c(a(x12)))))) ↔ a(c(a(a(c(a(x12)))))) ↔ a(c(a(b(a(b(x12)))))) ↔
t
/>