We consider the TRS containing the following rules:
| a(b(a(x))) | → | b(b(b(a(x)))) | (1) |
| b(b(b(a(x)))) | → | a(a(a(b(x)))) | (2) |
The underlying signature is as follows:
{a/1, b/1}| t0 | = | b(b(b(a(b(a(f3)))))) |
| → | b(b(b(b(b(b(a(f3))))))) | |
| = | t1 |
| t0 | = | b(b(b(a(b(a(f3)))))) |
| → | a(a(a(b(b(a(f3)))))) | |
| = | t1 |
Automaton 1
final states:
{1}
transitions:
| b(548) | → | 454 |
| b(93) | → | 643 |
| b(2) | → | 93 |
| b(207) | → | 376 |
| b(3) | → | 4 |
| b(6) | → | 7 |
| b(376) | → | 208 |
| b(7) | → | 8 |
| b(5) | → | 6 |
| b(453) | → | 548 |
| b(4) | → | 5 |
| b(94) | → | 453 |
| b(95) | → | 207 |
| b(8) | → | 1 |
| a(207) | → | 208 |
| a(2) | → | 3 |
| a(454) | → | 207 |
| a(95) | → | 6 |
| a(94) | → | 95 |
| a(93) | → | 94 |
| a(643) | → | 644 |
| a(453) | → | 454 |
| a(644) | → | 453 |
| a(208) | → | 209 |
| a(209) | → | 1 |
| f3 | → | 2 |
Automaton 2
final states:
{9}
transitions:
| b(11) | → | 12 |
| b(12) | → | 13 |
| a(14) | → | 15 |
| a(15) | → | 9 |
| a(10) | → | 11 |
| a(13) | → | 14 |
| f3 | → | 10 |