Certification Problem
Input (COPS 46)
We consider the TRS containing the following rules:
F(x,x) |
→ |
A |
(1) |
F(x,G(x)) |
→ |
B |
(2) |
C |
→ |
G(C) |
(3) |
The underlying signature is as follows:
{F/2, A/0, G/1, B/0, C/0}Property / Task
Prove or disprove confluence.Answer / Result
No.Proof (by csi @ CoCo 2023)
1 Non-Joinable Fork
The system is not confluent due to the following forking derivations.
t0
|
= |
F(C,C) |
|
→
|
F(C,G(C)) |
|
→
|
B |
|
= |
t2
|
The two resulting terms cannot be joined for the following reason:
- When applying the cap-function on both terms (where variables may be treated like constants)
then the resulting terms do not unify.