Certification Problem

Input (TPDB SRS_Standard/Secret_05_SRS/jambox4)

The rewrite relation of the following TRS is considered.

c(c(x1)) a(b(x1)) (1)
b(x1) a(a(x1)) (2)
b(b(b(x1))) a(c(b(x1))) (3)
a(c(a(x1))) a(c(c(x1))) (4)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by AProVE @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
c#(c(x1)) a#(b(x1)) (5)
c#(c(x1)) b#(x1) (6)
b#(x1) a#(a(x1)) (7)
b#(x1) a#(x1) (8)
b#(b(b(x1))) a#(c(b(x1))) (9)
b#(b(b(x1))) c#(b(x1)) (10)
a#(c(a(x1))) a#(c(c(x1))) (11)
a#(c(a(x1))) c#(c(x1)) (12)
a#(c(a(x1))) c#(x1) (13)

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.