Certification Problem
Input (TPDB SRS_Standard/Zantema_04/z037)
The rewrite relation of the following TRS is considered.
b(a(a(b(a(b(a(x1))))))) |
→ |
a(a(b(a(b(b(a(a(b(x1))))))))) |
(1) |
Property / Task
Prove or disprove termination.Answer / Result
Yes.Proof (by AProVE @ termCOMP 2023)
1 Dependency Pair Transformation
The following set of initial dependency pairs has been identified.
b#(a(a(b(a(b(a(x1))))))) |
→ |
b#(a(b(b(a(a(b(x1))))))) |
(2) |
b#(a(a(b(a(b(a(x1))))))) |
→ |
b#(b(a(a(b(x1))))) |
(3) |
b#(a(a(b(a(b(a(x1))))))) |
→ |
b#(a(a(b(x1)))) |
(4) |
b#(a(a(b(a(b(a(x1))))))) |
→ |
b#(x1) |
(5) |
1.1 Reduction Pair Processor
Using the matrix interpretations of dimension 3 with strict dimension 1 over the arctic semiring over the naturals
[b#(x1)] |
= |
+
|
-∞ |
0 |
-∞ |
-∞ |
-∞ |
-∞ |
-∞ |
-∞ |
-∞ |
|
|
· x1
|
[a(x1)] |
= |
+ · x1
|
[b(x1)] |
= |
+ · x1
|
the
pair
b#(a(a(b(a(b(a(x1))))))) |
→ |
b#(a(b(b(a(a(b(x1))))))) |
(2) |
could be deleted.
1.1.1 Reduction Pair Processor
Using the matrix interpretations of dimension 3 with strict dimension 1 over the arctic semiring over the naturals
[b#(x1)] |
= |
+
|
-∞ |
-∞ |
0 |
-∞ |
-∞ |
-∞ |
-∞ |
-∞ |
-∞ |
|
|
· x1
|
[a(x1)] |
= |
+ · x1
|
[b(x1)] |
= |
+ · x1
|
the
pairs
b#(a(a(b(a(b(a(x1))))))) |
→ |
b#(b(a(a(b(x1))))) |
(3) |
b#(a(a(b(a(b(a(x1))))))) |
→ |
b#(x1) |
(5) |
could be deleted.
1.1.1.1 Reduction Pair Processor
Using the matrix interpretations of dimension 3 with strict dimension 1 over the arctic semiring over the naturals
[b#(x1)] |
= |
+
|
-∞ |
0 |
-∞ |
-∞ |
-∞ |
-∞ |
-∞ |
-∞ |
-∞ |
|
|
· x1
|
[a(x1)] |
= |
+ · x1
|
[b(x1)] |
= |
+ · x1
|
the
pair
b#(a(a(b(a(b(a(x1))))))) |
→ |
b#(a(a(b(x1)))) |
(4) |
could be deleted.
1.1.1.1.1 P is empty
There are no pairs anymore.