Certification Problem
Input (TPDB SRS_Standard/Zantema_04/z042)
The rewrite relation of the following TRS is considered.
c(b(a(b(a(x1))))) |
→ |
a(b(a(b(a(b(c(b(c(x1))))))))) |
(1) |
Property / Task
Prove or disprove termination.Answer / Result
No.Proof (by AProVE @ termCOMP 2023)
1 Looping derivation
There is a looping derivation.
c b a b a b a b a b a b a →+ a b a b a b c b a b a b a b a b a b a b c b c b a b c b c
The derivation can be derived as follows.
-
c b a b a →+ a b a b a b c b c:
This is an original rule (OC1).
-
c b a b a b a b a →+ a b a b a b c b a b a b a b c b c:
The overlap closure is obtained from the following two overlap closures (OC2).
-
c b a b a →+ a b a b a b c b c
-
c b a b a →+ a b a b a b c b c
-
c b a b a b a b a →+ a b a b a b a b a b a b c b c b a b c b c:
The overlap closure is obtained from the following two overlap closures (OC3).
-
c b a b a b a b a →+ a b a b a b c b a b a b a b c b c
-
c b a b a →+ a b a b a b c b c
-
c b a b a b a b a b a b a →+ a b a b a b c b a b a b a b a b a b a b c b c b a b c b c:
The overlap closure is obtained from the following two overlap closures (OC2).
-
c b a b a →+ a b a b a b c b c
-
c b a b a b a b a →+ a b a b a b a b a b a b c b c b a b c b c