Certification Problem

Input (TPDB SRS_Standard/Zantema_06/13)

The rewrite relation of the following TRS is considered.

a(a(a(b(b(x1))))) b(b(b(x1))) (1)
b(a(a(a(b(x1))))) a(a(a(b(a(a(a(x1))))))) (2)
a(a(a(x1))) a(a(x1)) (3)
b(b(x1)) a(b(a(x1))) (4)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by AProVE @ termCOMP 2023)

1 Rule Removal

Using the linear polynomial interpretation over the naturals
[a(x1)] = 1 · x1 + 1
[b(x1)] = 1 · x1 + 3
all of the following rules can be deleted.
a(a(a(x1))) a(a(x1)) (3)
b(b(x1)) a(b(a(x1))) (4)

1.1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
a#(a(a(b(b(x1))))) b#(b(b(x1))) (5)
b#(a(a(a(b(x1))))) a#(a(a(b(a(a(a(x1))))))) (6)
b#(a(a(a(b(x1))))) a#(a(b(a(a(a(x1)))))) (7)
b#(a(a(a(b(x1))))) a#(b(a(a(a(x1))))) (8)
b#(a(a(a(b(x1))))) b#(a(a(a(x1)))) (9)
b#(a(a(a(b(x1))))) a#(a(a(x1))) (10)
b#(a(a(a(b(x1))))) a#(a(x1)) (11)
b#(a(a(a(b(x1))))) a#(x1) (12)

1.1.1 Monotonic Reduction Pair Processor

Using the linear polynomial interpretation over the naturals
[a(x1)] = 1 + 1 · x1
[b(x1)] = 3 + 1 · x1
[a#(x1)] = 1 · x1
[b#(x1)] = 2 + 1 · x1
the pairs
b#(a(a(a(b(x1))))) a#(a(b(a(a(a(x1)))))) (7)
b#(a(a(a(b(x1))))) a#(b(a(a(a(x1))))) (8)
b#(a(a(a(b(x1))))) b#(a(a(a(x1)))) (9)
b#(a(a(a(b(x1))))) a#(a(a(x1))) (10)
b#(a(a(a(b(x1))))) a#(a(x1)) (11)
b#(a(a(a(b(x1))))) a#(x1) (12)
and no rules could be deleted.

1.1.1.1 Reduction Pair Processor

Using the matrix interpretations of dimension 3 with strict dimension 1 over the arctic semiring over the naturals
[a#(x1)] =
-∞
-∞
-∞
+
0 0 0
-∞ -∞ -∞
-∞ -∞ -∞
· x1
[a(x1)] =
0
0
0
+
0 -∞ 0
0 -∞ -∞
0 -∞ -∞
· x1
[b(x1)] =
0
1
0
+
0 -∞ -∞
1 -∞ -∞
0 0 0
· x1
[b#(x1)] =
0
-∞
-∞
+
0 -∞ -∞
-∞ -∞ -∞
-∞ -∞ -∞
· x1
the pair
a#(a(a(b(b(x1))))) b#(b(b(x1))) (5)
could be deleted.

1.1.1.1.1 Reduction Pair Processor with Usable Rules

Using the non-linear polynomial interpretation over the naturals
[b#(x1)] = 1
[a(x1)] = 0
[b(x1)] = 0
[a#(x1)] = 0
having no usable rules (w.r.t. the implicit argument filter of the reduction pair), the pair
b#(a(a(a(b(x1))))) a#(a(a(b(a(a(a(x1))))))) (6)
could be deleted.

1.1.1.1.1.1 P is empty

There are no pairs anymore.