Certification Problem
Input (TPDB SRS_Standard/Secret_07_SRS/dj)
The rewrite relation of the following TRS is considered.
|
1(0(x1)) |
→ |
0(0(0(1(x1)))) |
(1) |
|
0(1(x1)) |
→ |
1(x1) |
(2) |
|
1(1(x1)) |
→ |
0(0(0(0(x1)))) |
(3) |
|
0(0(x1)) |
→ |
0(x1) |
(4) |
Property / Task
Prove or disprove termination.Answer / Result
Yes.Proof (by NaTT @ termCOMP 2023)
1 Dependency Pair Transformation
The following set of initial dependency pairs has been identified.
|
1#(1(x1)) |
→ |
0#(0(0(x1))) |
(5) |
|
1#(0(x1)) |
→ |
0#(0(1(x1))) |
(6) |
|
1#(0(x1)) |
→ |
0#(1(x1)) |
(7) |
|
1#(0(x1)) |
→ |
0#(0(0(1(x1)))) |
(8) |
|
1#(1(x1)) |
→ |
0#(0(x1)) |
(9) |
|
1#(1(x1)) |
→ |
0#(0(0(0(x1)))) |
(10) |
|
1#(0(x1)) |
→ |
1#(x1) |
(11) |
|
1#(1(x1)) |
→ |
0#(x1) |
(12) |
1.1 Dependency Graph Processor
The dependency pairs are split into 1
component.