Certification Problem

Input (TPDB SRS_Standard/Zantema_04/z115)

The rewrite relation of the following TRS is considered.

a(a(x1)) d(c(x1)) (1)
a(b(x1)) c(c(c(x1))) (2)
b(b(x1)) a(c(c(x1))) (3)
c(c(x1)) b(x1) (4)
c(d(x1)) a(a(x1)) (5)
d(d(x1)) b(a(c(x1))) (6)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by NaTT @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
a#(b(x1)) c#(c(x1)) (7)
d#(d(x1)) c#(x1) (8)
a#(a(x1)) c#(x1) (9)
b#(b(x1)) a#(c(c(x1))) (10)
b#(b(x1)) c#(x1) (11)
a#(a(x1)) d#(c(x1)) (12)
c#(c(x1)) b#(x1) (13)
c#(d(x1)) a#(a(x1)) (14)
b#(b(x1)) c#(c(x1)) (15)
d#(d(x1)) a#(c(x1)) (16)
a#(b(x1)) c#(x1) (17)
a#(b(x1)) c#(c(c(x1))) (18)
c#(d(x1)) a#(x1) (19)
d#(d(x1)) b#(a(c(x1))) (20)

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.