The rewrite relation of the following TRS is considered.
a(a(x1)) | → | d(c(x1)) | (1) |
a(b(x1)) | → | c(c(c(x1))) | (2) |
b(b(x1)) | → | a(c(c(x1))) | (3) |
c(c(x1)) | → | b(x1) | (4) |
c(d(x1)) | → | a(a(x1)) | (5) |
d(d(x1)) | → | b(a(c(x1))) | (6) |
a#(b(x1)) | → | c#(c(x1)) | (7) |
d#(d(x1)) | → | c#(x1) | (8) |
a#(a(x1)) | → | c#(x1) | (9) |
b#(b(x1)) | → | a#(c(c(x1))) | (10) |
b#(b(x1)) | → | c#(x1) | (11) |
a#(a(x1)) | → | d#(c(x1)) | (12) |
c#(c(x1)) | → | b#(x1) | (13) |
c#(d(x1)) | → | a#(a(x1)) | (14) |
b#(b(x1)) | → | c#(c(x1)) | (15) |
d#(d(x1)) | → | a#(c(x1)) | (16) |
a#(b(x1)) | → | c#(x1) | (17) |
a#(b(x1)) | → | c#(c(c(x1))) | (18) |
c#(d(x1)) | → | a#(x1) | (19) |
d#(d(x1)) | → | b#(a(c(x1))) | (20) |
The dependency pairs are split into 1 component.
d#(d(x1)) | → | b#(a(c(x1))) | (20) |
c#(c(x1)) | → | b#(x1) | (13) |
a#(a(x1)) | → | d#(c(x1)) | (12) |
c#(d(x1)) | → | a#(x1) | (19) |
a#(b(x1)) | → | c#(c(c(x1))) | (18) |
a#(b(x1)) | → | c#(x1) | (17) |
b#(b(x1)) | → | c#(x1) | (11) |
b#(b(x1)) | → | a#(c(c(x1))) | (10) |
a#(a(x1)) | → | c#(x1) | (9) |
d#(d(x1)) | → | c#(x1) | (8) |
d#(d(x1)) | → | a#(c(x1)) | (16) |
b#(b(x1)) | → | c#(c(x1)) | (15) |
c#(d(x1)) | → | a#(a(x1)) | (14) |
a#(b(x1)) | → | c#(c(x1)) | (7) |
[a(x1)] | = | x1 + 19502 |
[d(x1)] | = | x1 + 26816 |
[b(x1)] | = | x1 + 21939 |
[c(x1)] | = | x1 + 12188 |
[d#(x1)] | = | x1 + 9751 |
[c#(x1)] | = | x1 + 0 |
[a#(x1)] | = | x1 + 2438 |
[b#(x1)] | = | x1 + 4876 |
c(c(x1)) | → | b(x1) | (4) |
a(a(x1)) | → | d(c(x1)) | (1) |
b(b(x1)) | → | a(c(c(x1))) | (3) |
c(d(x1)) | → | a(a(x1)) | (5) |
d(d(x1)) | → | b(a(c(x1))) | (6) |
a(b(x1)) | → | c(c(c(x1))) | (2) |
d#(d(x1)) | → | b#(a(c(x1))) | (20) |
c#(c(x1)) | → | b#(x1) | (13) |
a#(a(x1)) | → | d#(c(x1)) | (12) |
c#(d(x1)) | → | a#(x1) | (19) |
a#(b(x1)) | → | c#(c(c(x1))) | (18) |
a#(b(x1)) | → | c#(x1) | (17) |
b#(b(x1)) | → | c#(x1) | (11) |
b#(b(x1)) | → | a#(c(c(x1))) | (10) |
a#(a(x1)) | → | c#(x1) | (9) |
d#(d(x1)) | → | c#(x1) | (8) |
d#(d(x1)) | → | a#(c(x1)) | (16) |
b#(b(x1)) | → | c#(c(x1)) | (15) |
c#(d(x1)) | → | a#(a(x1)) | (14) |
a#(b(x1)) | → | c#(c(x1)) | (7) |
The dependency pairs are split into 0 components.