Certification Problem

Input (TPDB SRS_Standard/ICFP_2010/214169)

The rewrite relation of the following TRS is considered.

0(0(1(x1))) 0(0(2(1(3(x1))))) (1)
0(0(1(x1))) 0(0(2(2(3(1(x1)))))) (2)
0(4(1(x1))) 0(4(2(2(1(x1))))) (3)
0(4(1(x1))) 0(2(3(1(4(2(x1)))))) (4)
1(0(1(x1))) 0(2(1(1(x1)))) (5)
1(0(1(x1))) 0(2(1(1(2(x1))))) (6)
1(0(1(x1))) 1(0(3(2(1(x1))))) (7)
1(4(0(x1))) 1(0(3(2(4(2(x1)))))) (8)
1(4(1(x1))) 4(2(1(1(x1)))) (9)
1(4(1(x1))) 4(2(1(1(2(1(x1)))))) (10)
4(0(1(x1))) 4(0(2(1(x1)))) (11)
5(0(1(x1))) 5(0(2(1(x1)))) (12)
5(0(1(x1))) 0(2(1(5(3(x1))))) (13)
5(0(1(x1))) 0(3(2(1(5(5(x1)))))) (14)
5(0(1(x1))) 3(0(2(3(5(1(x1)))))) (15)
5(0(5(x1))) 0(3(2(5(3(5(x1)))))) (16)
5(4(1(x1))) 2(4(2(5(1(3(x1)))))) (17)
5(4(1(x1))) 4(5(2(1(3(3(x1)))))) (18)
0(0(4(5(x1)))) 0(5(0(2(4(2(x1)))))) (19)
0(1(2(0(x1)))) 2(0(2(1(0(x1))))) (20)
0(2(0(1(x1)))) 0(0(2(1(3(x1))))) (21)
0(3(4(0(x1)))) 3(2(4(0(0(3(x1)))))) (22)
0(4(0(4(x1)))) 0(0(3(2(4(4(x1)))))) (23)
1(0(1(4(x1)))) 2(3(1(1(4(0(x1)))))) (24)
1(0(3(1(x1)))) 4(2(3(1(1(0(x1)))))) (25)
1(2(0(4(x1)))) 1(4(2(0(3(2(x1)))))) (26)
1(3(0(4(x1)))) 4(0(3(2(1(3(x1)))))) (27)
1(4(1(5(x1)))) 2(1(2(5(1(4(x1)))))) (28)
4(0(5(1(x1)))) 0(2(4(2(1(5(x1)))))) (29)
4(1(0(0(x1)))) 3(2(1(4(0(0(x1)))))) (30)
4(1(0(4(x1)))) 4(4(0(2(1(x1))))) (31)
5(0(0(1(x1)))) 0(3(2(5(1(0(x1)))))) (32)
5(0(3(1(x1)))) 0(5(3(2(1(x1))))) (33)
5(0(3(1(x1)))) 0(3(5(2(2(1(x1)))))) (34)
5(0(5(1(x1)))) 5(2(5(3(1(0(x1)))))) (35)
5(2(4(1(x1)))) 2(1(4(2(5(x1))))) (36)
5(4(1(5(x1)))) 4(5(5(2(1(x1))))) (37)
5(4(1(5(x1)))) 2(1(5(4(2(5(x1)))))) (38)
5(4(3(1(x1)))) 5(4(2(1(3(x1))))) (39)
5(4(3(1(x1)))) 3(5(2(4(2(1(x1)))))) (40)
5(4(3(1(x1)))) 5(2(4(3(2(1(x1)))))) (41)
5(5(0(4(x1)))) 5(0(2(5(4(2(x1)))))) (42)
0(0(3(3(1(x1))))) 0(3(0(1(2(3(x1)))))) (43)
0(2(4(3(1(x1))))) 0(2(3(1(4(2(x1)))))) (44)
0(5(4(1(1(x1))))) 4(0(2(5(1(1(x1)))))) (45)
1(2(4(3(1(x1))))) 1(2(3(3(1(4(x1)))))) (46)
4(0(0(3(1(x1))))) 4(0(3(2(1(0(x1)))))) (47)
4(0(0(3(1(x1))))) 4(3(2(0(0(1(x1)))))) (48)
5(1(0(0(5(x1))))) 5(0(0(2(1(5(x1)))))) (49)
5(4(2(0(1(x1))))) 2(5(4(0(2(1(x1)))))) (50)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by matchbox @ termCOMP 2023)

1 String Reversal

Since only unary symbols occur, one can reverse all terms and obtains the TRS
1(0(0(x1))) 3(1(2(0(0(x1))))) (51)
1(0(0(x1))) 1(3(2(2(0(0(x1)))))) (52)
1(4(0(x1))) 1(2(2(4(0(x1))))) (53)
1(4(0(x1))) 2(4(1(3(2(0(x1)))))) (54)
1(0(1(x1))) 1(1(2(0(x1)))) (55)
1(0(1(x1))) 2(1(1(2(0(x1))))) (56)
1(0(1(x1))) 1(2(3(0(1(x1))))) (57)
0(4(1(x1))) 2(4(2(3(0(1(x1)))))) (58)
1(4(1(x1))) 1(1(2(4(x1)))) (59)
1(4(1(x1))) 1(2(1(1(2(4(x1)))))) (60)
1(0(4(x1))) 1(2(0(4(x1)))) (61)
1(0(5(x1))) 1(2(0(5(x1)))) (62)
1(0(5(x1))) 3(5(1(2(0(x1))))) (63)
1(0(5(x1))) 5(5(1(2(3(0(x1)))))) (64)
1(0(5(x1))) 1(5(3(2(0(3(x1)))))) (65)
5(0(5(x1))) 5(3(5(2(3(0(x1)))))) (66)
1(4(5(x1))) 3(1(5(2(4(2(x1)))))) (67)
1(4(5(x1))) 3(3(1(2(5(4(x1)))))) (68)
5(4(0(0(x1)))) 2(4(2(0(5(0(x1)))))) (69)
0(2(1(0(x1)))) 0(1(2(0(2(x1))))) (70)
1(0(2(0(x1)))) 3(1(2(0(0(x1))))) (71)
0(4(3(0(x1)))) 3(0(0(4(2(3(x1)))))) (72)
4(0(4(0(x1)))) 4(4(2(3(0(0(x1)))))) (73)
4(1(0(1(x1)))) 0(4(1(1(3(2(x1)))))) (74)
1(3(0(1(x1)))) 0(1(1(3(2(4(x1)))))) (75)
4(0(2(1(x1)))) 2(3(0(2(4(1(x1)))))) (76)
4(0(3(1(x1)))) 3(1(2(3(0(4(x1)))))) (77)
5(1(4(1(x1)))) 4(1(5(2(1(2(x1)))))) (78)
1(5(0(4(x1)))) 5(1(2(4(2(0(x1)))))) (79)
0(0(1(4(x1)))) 0(0(4(1(2(3(x1)))))) (80)
4(0(1(4(x1)))) 1(2(0(4(4(x1))))) (81)
1(0(0(5(x1)))) 0(1(5(2(3(0(x1)))))) (82)
1(3(0(5(x1)))) 1(2(3(5(0(x1))))) (83)
1(3(0(5(x1)))) 1(2(2(5(3(0(x1)))))) (84)
1(5(0(5(x1)))) 0(1(3(5(2(5(x1)))))) (85)
1(4(2(5(x1)))) 5(2(4(1(2(x1))))) (86)
5(1(4(5(x1)))) 1(2(5(5(4(x1))))) (87)
5(1(4(5(x1)))) 5(2(4(5(1(2(x1)))))) (88)
1(3(4(5(x1)))) 3(1(2(4(5(x1))))) (89)
1(3(4(5(x1)))) 1(2(4(2(5(3(x1)))))) (90)
1(3(4(5(x1)))) 1(2(3(4(2(5(x1)))))) (91)
4(0(5(5(x1)))) 2(4(5(2(0(5(x1)))))) (92)
1(3(3(0(0(x1))))) 3(2(1(0(3(0(x1)))))) (93)
1(3(4(2(0(x1))))) 2(4(1(3(2(0(x1)))))) (94)
1(1(4(5(0(x1))))) 1(1(5(2(0(4(x1)))))) (95)
1(3(4(2(1(x1))))) 4(1(3(3(2(1(x1)))))) (96)
1(3(0(0(4(x1))))) 0(1(2(3(0(4(x1)))))) (97)
1(3(0(0(4(x1))))) 1(0(0(2(3(4(x1)))))) (98)
5(0(0(1(5(x1))))) 5(1(2(0(0(5(x1)))))) (99)
1(0(2(4(5(x1))))) 1(2(0(4(5(2(x1)))))) (100)

1.1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.

There are 133 ruless (increase limit for explicit display).

1.1.1 Monotonic Reduction Pair Processor with Usable Rules

Using the matrix interpretations of dimension 1 with strict dimension 1 over the rationals with delta = 1
[5(x1)] = x1 +
0
[4(x1)] = x1 +
0
[3(x1)] = x1 +
0
[2(x1)] = x1 +
0
[1(x1)] = x1 +
0
[0(x1)] = x1 +
1
[5#(x1)] = x1 +
0
[4#(x1)] = x1 +
0
[1#(x1)] = x1 +
0
[0#(x1)] = x1 +
1
together with the usable rules
1(0(0(x1))) 3(1(2(0(0(x1))))) (51)
1(0(0(x1))) 1(3(2(2(0(0(x1)))))) (52)
1(4(0(x1))) 1(2(2(4(0(x1))))) (53)
1(4(0(x1))) 2(4(1(3(2(0(x1)))))) (54)
1(0(1(x1))) 1(1(2(0(x1)))) (55)
1(0(1(x1))) 2(1(1(2(0(x1))))) (56)
1(0(1(x1))) 1(2(3(0(1(x1))))) (57)
0(4(1(x1))) 2(4(2(3(0(1(x1)))))) (58)
1(4(1(x1))) 1(1(2(4(x1)))) (59)
1(4(1(x1))) 1(2(1(1(2(4(x1)))))) (60)
1(0(4(x1))) 1(2(0(4(x1)))) (61)
1(0(5(x1))) 1(2(0(5(x1)))) (62)
1(0(5(x1))) 3(5(1(2(0(x1))))) (63)
1(0(5(x1))) 5(5(1(2(3(0(x1)))))) (64)
1(0(5(x1))) 1(5(3(2(0(3(x1)))))) (65)
5(0(5(x1))) 5(3(5(2(3(0(x1)))))) (66)
1(4(5(x1))) 3(1(5(2(4(2(x1)))))) (67)
1(4(5(x1))) 3(3(1(2(5(4(x1)))))) (68)
5(4(0(0(x1)))) 2(4(2(0(5(0(x1)))))) (69)
0(2(1(0(x1)))) 0(1(2(0(2(x1))))) (70)
1(0(2(0(x1)))) 3(1(2(0(0(x1))))) (71)
0(4(3(0(x1)))) 3(0(0(4(2(3(x1)))))) (72)
4(0(4(0(x1)))) 4(4(2(3(0(0(x1)))))) (73)
4(1(0(1(x1)))) 0(4(1(1(3(2(x1)))))) (74)
1(3(0(1(x1)))) 0(1(1(3(2(4(x1)))))) (75)
4(0(2(1(x1)))) 2(3(0(2(4(1(x1)))))) (76)
4(0(3(1(x1)))) 3(1(2(3(0(4(x1)))))) (77)
5(1(4(1(x1)))) 4(1(5(2(1(2(x1)))))) (78)
1(5(0(4(x1)))) 5(1(2(4(2(0(x1)))))) (79)
0(0(1(4(x1)))) 0(0(4(1(2(3(x1)))))) (80)
4(0(1(4(x1)))) 1(2(0(4(4(x1))))) (81)
1(0(0(5(x1)))) 0(1(5(2(3(0(x1)))))) (82)
1(3(0(5(x1)))) 1(2(3(5(0(x1))))) (83)
1(3(0(5(x1)))) 1(2(2(5(3(0(x1)))))) (84)
1(5(0(5(x1)))) 0(1(3(5(2(5(x1)))))) (85)
1(4(2(5(x1)))) 5(2(4(1(2(x1))))) (86)
5(1(4(5(x1)))) 1(2(5(5(4(x1))))) (87)
5(1(4(5(x1)))) 5(2(4(5(1(2(x1)))))) (88)
1(3(4(5(x1)))) 3(1(2(4(5(x1))))) (89)
1(3(4(5(x1)))) 1(2(4(2(5(3(x1)))))) (90)
1(3(4(5(x1)))) 1(2(3(4(2(5(x1)))))) (91)
4(0(5(5(x1)))) 2(4(5(2(0(5(x1)))))) (92)
1(3(3(0(0(x1))))) 3(2(1(0(3(0(x1)))))) (93)
1(3(4(2(0(x1))))) 2(4(1(3(2(0(x1)))))) (94)
1(1(4(5(0(x1))))) 1(1(5(2(0(4(x1)))))) (95)
1(3(4(2(1(x1))))) 4(1(3(3(2(1(x1)))))) (96)
1(3(0(0(4(x1))))) 0(1(2(3(0(4(x1)))))) (97)
1(3(0(0(4(x1))))) 1(0(0(2(3(4(x1)))))) (98)
5(0(0(1(5(x1))))) 5(1(2(0(0(5(x1)))))) (99)
1(0(2(4(5(x1))))) 1(2(0(4(5(2(x1)))))) (100)
(w.r.t. the implicit argument filter of the reduction pair), the pairs
5#(4(0(0(x1)))) 5#(0(x1)) (101)
5#(0(0(1(5(x1))))) 0#(5(x1)) (121)
4#(1(0(1(x1)))) 4#(1(1(3(2(x1))))) (123)
4#(1(0(1(x1)))) 1#(3(2(x1))) (124)
4#(1(0(1(x1)))) 1#(1(3(2(x1)))) (125)
4#(0(3(1(x1)))) 4#(x1) (133)
4#(0(2(1(x1)))) 4#(1(x1)) (136)
4#(0(1(4(x1)))) 4#(4(x1)) (138)
1#(5(0(5(x1)))) 5#(2(5(x1))) (141)
1#(5(0(5(x1)))) 1#(3(5(2(5(x1))))) (142)
1#(3(0(1(x1)))) 4#(x1) (181)
1#(3(0(1(x1)))) 1#(3(2(4(x1)))) (182)
1#(3(0(1(x1)))) 1#(1(3(2(4(x1))))) (183)
1#(3(0(0(4(x1))))) 1#(2(3(0(4(x1))))) (185)
1#(3(0(0(4(x1))))) 0#(2(3(4(x1)))) (187)
1#(1(4(5(0(x1))))) 4#(x1) (191)
1#(0(2(4(5(x1))))) 5#(2(x1)) (206)
1#(0(2(4(5(x1))))) 4#(5(2(x1))) (207)
1#(0(0(5(x1)))) 5#(2(3(0(x1)))) (218)
1#(0(0(5(x1)))) 1#(5(2(3(0(x1))))) (219)
1#(0(0(5(x1)))) 0#(x1) (220)
0#(4(3(0(x1)))) 4#(2(3(x1))) (222)
0#(4(3(0(x1)))) 0#(4(2(3(x1)))) (223)
0#(2(1(0(x1)))) 1#(2(0(2(x1)))) (227)
0#(2(1(0(x1)))) 0#(2(x1)) (228)
0#(0(1(4(x1)))) 4#(1(2(3(x1)))) (230)
0#(0(1(4(x1)))) 1#(2(3(x1))) (231)
0#(0(1(4(x1)))) 0#(4(1(2(3(x1))))) (232)
and no rules could be deleted.

1.1.1.1 Dependency Graph Processor

The dependency pairs are split into 2 components.