The rewrite relation of the following TRS is considered.
a(d(x1)) | → | d(b(c(b(d(x1))))) | (1) |
a(x1) | → | b(b(f(b(b(x1))))) | (2) |
b(d(b(x1))) | → | a(d(x1)) | (3) |
d(f(x1)) | → | b(d(x1)) | (4) |
d(a(x1)) | → | d(b(c(b(d(x1))))) | (5) |
a(x1) | → | b(b(f(b(b(x1))))) | (2) |
b(d(b(x1))) | → | d(a(x1)) | (6) |
f(d(x1)) | → | d(b(x1)) | (7) |
f#(d(x1)) | → | d#(b(x1)) | (8) |
f#(d(x1)) | → | b#(x1) | (9) |
d#(a(x1)) | → | d#(x1) | (10) |
d#(a(x1)) | → | d#(b(c(b(d(x1))))) | (11) |
d#(a(x1)) | → | b#(d(x1)) | (12) |
d#(a(x1)) | → | b#(c(b(d(x1)))) | (13) |
b#(d(b(x1))) | → | d#(a(x1)) | (14) |
b#(d(b(x1))) | → | a#(x1) | (15) |
a#(x1) | → | f#(b(b(x1))) | (16) |
a#(x1) | → | b#(x1) | (17) |
a#(x1) | → | b#(f(b(b(x1)))) | (18) |
a#(x1) | → | b#(b(x1)) | (19) |
a#(x1) | → | b#(b(f(b(b(x1))))) | (20) |
The dependency pairs are split into 1 component.
f#(d(x1)) | → | d#(b(x1)) | (8) |
d#(a(x1)) | → | d#(x1) | (10) |
d#(a(x1)) | → | b#(d(x1)) | (12) |
b#(d(b(x1))) | → | d#(a(x1)) | (14) |
b#(d(b(x1))) | → | a#(x1) | (15) |
a#(x1) | → | f#(b(b(x1))) | (16) |
f#(d(x1)) | → | b#(x1) | (9) |
a#(x1) | → | b#(x1) | (17) |
a#(x1) | → | b#(f(b(b(x1)))) | (18) |
a#(x1) | → | b#(b(x1)) | (19) |
a#(x1) | → | b#(b(f(b(b(x1))))) | (20) |
[f(x1)] | = |
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[d(x1)] | = |
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[c(x1)] | = |
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[b(x1)] | = |
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[a(x1)] | = |
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[f#(x1)] | = |
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[d#(x1)] | = |
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[b#(x1)] | = |
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[a#(x1)] | = |
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d(a(x1)) | → | d(b(c(b(d(x1))))) | (5) |
a(x1) | → | b(b(f(b(b(x1))))) | (2) |
b(d(b(x1))) | → | d(a(x1)) | (6) |
f(d(x1)) | → | d(b(x1)) | (7) |
a#(x1) | → | f#(b(b(x1))) | (16) |
[f(x1)] | = |
x1 +
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[d(x1)] | = |
x1 +
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[c(x1)] | = |
x1 +
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[b(x1)] | = |
x1 +
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[a(x1)] | = |
x1 +
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[f#(x1)] | = |
x1 +
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[d#(x1)] | = |
x1 +
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[b#(x1)] | = |
x1 +
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[a#(x1)] | = |
x1 +
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d(a(x1)) | → | d(b(c(b(d(x1))))) | (5) |
a(x1) | → | b(b(f(b(b(x1))))) | (2) |
b(d(b(x1))) | → | d(a(x1)) | (6) |
f(d(x1)) | → | d(b(x1)) | (7) |
f#(d(x1)) | → | d#(b(x1)) | (8) |
f#(d(x1)) | → | b#(x1) | (9) |
The dependency pairs are split into 1 component.
d#(a(x1)) | → | d#(x1) | (10) |
d#(a(x1)) | → | b#(d(x1)) | (12) |
b#(d(b(x1))) | → | d#(a(x1)) | (14) |
b#(d(b(x1))) | → | a#(x1) | (15) |
a#(x1) | → | b#(x1) | (17) |
a#(x1) | → | b#(f(b(b(x1)))) | (18) |
a#(x1) | → | b#(b(x1)) | (19) |
a#(x1) | → | b#(b(f(b(b(x1))))) | (20) |
[f(x1)] | = |
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[d(x1)] | = |
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[c(x1)] | = |
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[b(x1)] | = |
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[a(x1)] | = |
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[d#(x1)] | = |
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[b#(x1)] | = |
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[a#(x1)] | = |
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d(a(x1)) | → | d(b(c(b(d(x1))))) | (5) |
a(x1) | → | b(b(f(b(b(x1))))) | (2) |
b(d(b(x1))) | → | d(a(x1)) | (6) |
f(d(x1)) | → | d(b(x1)) | (7) |
b#(d(b(x1))) | → | a#(x1) | (15) |
[f(x1)] | = |
x1 +
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[d(x1)] | = |
x1 +
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[c(x1)] | = |
x1 +
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[b(x1)] | = |
x1 +
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[a(x1)] | = |
x1 +
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[d#(x1)] | = |
x1 +
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[b#(x1)] | = |
x1 +
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[a#(x1)] | = |
x1 +
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d(a(x1)) | → | d(b(c(b(d(x1))))) | (5) |
a(x1) | → | b(b(f(b(b(x1))))) | (2) |
b(d(b(x1))) | → | d(a(x1)) | (6) |
f(d(x1)) | → | d(b(x1)) | (7) |
a#(x1) | → | b#(x1) | (17) |
a#(x1) | → | b#(f(b(b(x1)))) | (18) |
a#(x1) | → | b#(b(x1)) | (19) |
a#(x1) | → | b#(b(f(b(b(x1))))) | (20) |
The dependency pairs are split into 1 component.
d#(a(x1)) | → | d#(x1) | (10) |
d#(a(x1)) | → | b#(d(x1)) | (12) |
b#(d(b(x1))) | → | d#(a(x1)) | (14) |
[f(x1)] | = |
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[d(x1)] | = |
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[c(x1)] | = |
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[b(x1)] | = |
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[a(x1)] | = |
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[d#(x1)] | = |
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[b#(x1)] | = |
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d(a(x1)) | → | d(b(c(b(d(x1))))) | (5) |
a(x1) | → | b(b(f(b(b(x1))))) | (2) |
b(d(b(x1))) | → | d(a(x1)) | (6) |
f(d(x1)) | → | d(b(x1)) | (7) |
d#(a(x1)) | → | d#(x1) | (10) |
The dependency pairs are split into 1 component.
d#(a(x1)) | → | b#(d(x1)) | (12) |
b#(d(b(x1))) | → | d#(a(x1)) | (14) |
[f(x1)] | = |
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[d(x1)] | = |
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[c(x1)] | = |
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[b(x1)] | = |
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[a(x1)] | = |
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[d#(x1)] | = |
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[b#(x1)] | = |
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d(a(x1)) | → | d(b(c(b(d(x1))))) | (5) |
a(x1) | → | b(b(f(b(b(x1))))) | (2) |
b(d(b(x1))) | → | d(a(x1)) | (6) |
f(d(x1)) | → | d(b(x1)) | (7) |
d#(a(x1)) | → | b#(d(x1)) | (12) |
[f(x1)] | = |
x1 +
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[d(x1)] | = |
x1 +
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[c(x1)] | = |
x1 +
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[b(x1)] | = |
x1 +
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[a(x1)] | = |
x1 +
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[d#(x1)] | = |
x1 +
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[b#(x1)] | = |
x1 +
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d(a(x1)) | → | d(b(c(b(d(x1))))) | (5) |
a(x1) | → | b(b(f(b(b(x1))))) | (2) |
b(d(b(x1))) | → | d(a(x1)) | (6) |
f(d(x1)) | → | d(b(x1)) | (7) |
b#(d(b(x1))) | → | d#(a(x1)) | (14) |
The dependency pairs are split into 0 components.