Certification Problem
Input (TPDB SRS_Standard/Secret_05_SRS/torpa4)
The rewrite relation of the following TRS is considered.
a(b(c(a(x1)))) |
→ |
b(a(c(b(a(b(x1)))))) |
(1) |
a(d(x1)) |
→ |
c(x1) |
(2) |
a(f(f(x1))) |
→ |
g(x1) |
(3) |
b(g(x1)) |
→ |
g(b(x1)) |
(4) |
c(x1) |
→ |
f(f(x1)) |
(5) |
c(a(c(x1))) |
→ |
b(c(a(b(c(x1))))) |
(6) |
c(d(x1)) |
→ |
a(a(x1)) |
(7) |
g(x1) |
→ |
c(a(x1)) |
(8) |
g(x1) |
→ |
d(d(d(d(x1)))) |
(9) |
Property / Task
Prove or disprove termination.Answer / Result
Yes.Proof (by matchbox @ termCOMP 2023)
1 Rule Removal
Using the
matrix interpretations of dimension 1 with strict dimension 1 over the rationals with delta = 1
[g(x1)] |
= |
x1 +
|
[f(x1)] |
= |
x1 +
|
[d(x1)] |
= |
x1 +
|
[c(x1)] |
= |
x1 +
|
[b(x1)] |
= |
x1 +
|
[a(x1)] |
= |
x1 +
|
all of the following rules can be deleted.
a(d(x1)) |
→ |
c(x1) |
(2) |
c(d(x1)) |
→ |
a(a(x1)) |
(7) |
g(x1) |
→ |
d(d(d(d(x1)))) |
(9) |
1.1 String Reversal
Since only unary symbols occur, one can reverse all terms and obtains the TRS
a(c(b(a(x1)))) |
→ |
b(a(b(c(a(b(x1)))))) |
(10) |
f(f(a(x1))) |
→ |
g(x1) |
(11) |
g(b(x1)) |
→ |
b(g(x1)) |
(12) |
c(x1) |
→ |
f(f(x1)) |
(5) |
c(a(c(x1))) |
→ |
c(b(a(c(b(x1))))) |
(13) |
g(x1) |
→ |
a(c(x1)) |
(14) |
1.1.1 Dependency Pair Transformation
The following set of initial dependency pairs has been identified.
g#(x1) |
→ |
c#(x1) |
(15) |
g#(x1) |
→ |
a#(c(x1)) |
(16) |
g#(b(x1)) |
→ |
g#(x1) |
(17) |
f#(f(a(x1))) |
→ |
g#(x1) |
(18) |
c#(x1) |
→ |
f#(x1) |
(19) |
c#(x1) |
→ |
f#(f(x1)) |
(20) |
c#(a(c(x1))) |
→ |
c#(b(x1)) |
(21) |
c#(a(c(x1))) |
→ |
c#(b(a(c(b(x1))))) |
(22) |
c#(a(c(x1))) |
→ |
a#(c(b(x1))) |
(23) |
a#(c(b(a(x1)))) |
→ |
c#(a(b(x1))) |
(24) |
a#(c(b(a(x1)))) |
→ |
a#(b(x1)) |
(25) |
a#(c(b(a(x1)))) |
→ |
a#(b(c(a(b(x1))))) |
(26) |
1.1.1.1 Monotonic Reduction Pair Processor with Usable Rules
Using the matrix interpretations of dimension 1 with strict dimension 1 over the rationals with delta = 1
[g(x1)] |
= |
x1 +
|
[f(x1)] |
= |
x1 +
|
[c(x1)] |
= |
x1 +
|
[b(x1)] |
= |
x1 +
|
[a(x1)] |
= |
x1 +
|
[g#(x1)] |
= |
x1 +
|
[f#(x1)] |
= |
x1 +
|
[c#(x1)] |
= |
x1 +
|
[a#(x1)] |
= |
x1 +
|
together with the usable
rules
a(c(b(a(x1)))) |
→ |
b(a(b(c(a(b(x1)))))) |
(10) |
f(f(a(x1))) |
→ |
g(x1) |
(11) |
g(b(x1)) |
→ |
b(g(x1)) |
(12) |
c(x1) |
→ |
f(f(x1)) |
(5) |
c(a(c(x1))) |
→ |
c(b(a(c(b(x1))))) |
(13) |
g(x1) |
→ |
a(c(x1)) |
(14) |
(w.r.t. the implicit argument filter of the reduction pair),
the
pairs
g#(x1) |
→ |
c#(x1) |
(15) |
g#(x1) |
→ |
a#(c(x1)) |
(16) |
f#(f(a(x1))) |
→ |
g#(x1) |
(18) |
c#(x1) |
→ |
f#(x1) |
(19) |
c#(x1) |
→ |
f#(f(x1)) |
(20) |
c#(a(c(x1))) |
→ |
c#(b(x1)) |
(21) |
c#(a(c(x1))) |
→ |
a#(c(b(x1))) |
(23) |
a#(c(b(a(x1)))) |
→ |
c#(a(b(x1))) |
(24) |
a#(c(b(a(x1)))) |
→ |
a#(b(x1)) |
(25) |
and
no rules
could be deleted.
1.1.1.1.1 Dependency Graph Processor
The dependency pairs are split into 1
component.