Certification Problem

Input (TPDB SRS_Standard/Secret_07_SRS/x02)

The rewrite relation of the following TRS is considered.

a(b(x1)) c(d(x1)) (1)
d(d(x1)) b(e(x1)) (2)
b(x1) d(c(x1)) (3)
d(x1) x1 (4)
e(c(x1)) d(a(x1)) (5)
a(x1) e(d(x1)) (6)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by matchbox @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
e#(c(x1)) d#(a(x1)) (7)
e#(c(x1)) a#(x1) (8)
d#(d(x1)) e#(x1) (9)
d#(d(x1)) b#(e(x1)) (10)
b#(x1) d#(c(x1)) (11)
a#(x1) e#(d(x1)) (12)
a#(x1) d#(x1) (13)
a#(b(x1)) d#(x1) (14)

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.