Certification Problem
Input (TPDB SRS_Standard/Waldmann_06_SRS/uni-1)
The rewrite relation of the following TRS is considered.
a(a(a(x1))) |
→ |
a(c(a(a(x1)))) |
(1) |
c(c(c(x1))) |
→ |
a(x1) |
(2) |
a(x1) |
→ |
x1 |
(3) |
Property / Task
Prove or disprove termination.Answer / Result
Yes.Proof (by matchbox @ termCOMP 2023)
1 Closure Under Flat Contexts
Using the flat contexts
{c(☐), a(☐)}
We obtain the transformed TRS
c(a(a(a(x1)))) |
→ |
c(a(c(a(a(x1))))) |
(4) |
c(c(c(c(x1)))) |
→ |
c(a(x1)) |
(5) |
c(a(x1)) |
→ |
c(x1) |
(6) |
a(a(a(a(x1)))) |
→ |
a(a(c(a(a(x1))))) |
(7) |
a(c(c(c(x1)))) |
→ |
a(a(x1)) |
(8) |
a(a(x1)) |
→ |
a(x1) |
(9) |
1.1 Semantic Labeling
The following interpretations form a
model
of the rules.
As carrier we take the set
{0,1}.
Symbols are labeled by the interpretation of their arguments using the interpretations
(modulo 2):
[c(x1)] |
= |
2x1 + 0 |
[a(x1)] |
= |
2x1 + 1 |
We obtain the labeled TRS
a1(a1(a1(a1(x1)))) |
→ |
a1(a0(c1(a1(a1(x1))))) |
(10) |
a1(a1(a1(a0(x1)))) |
→ |
a1(a0(c1(a1(a0(x1))))) |
(11) |
c1(a1(a1(a1(x1)))) |
→ |
c1(a0(c1(a1(a1(x1))))) |
(12) |
c1(a1(a1(a0(x1)))) |
→ |
c1(a0(c1(a1(a0(x1))))) |
(13) |
a0(c0(c0(c1(x1)))) |
→ |
a1(a1(x1)) |
(14) |
a0(c0(c0(c0(x1)))) |
→ |
a1(a0(x1)) |
(15) |
c0(c0(c0(c1(x1)))) |
→ |
c1(a1(x1)) |
(16) |
c0(c0(c0(c0(x1)))) |
→ |
c1(a0(x1)) |
(17) |
a1(a1(x1)) |
→ |
a1(x1) |
(18) |
a1(a0(x1)) |
→ |
a0(x1) |
(19) |
c1(a1(x1)) |
→ |
c1(x1) |
(20) |
c1(a0(x1)) |
→ |
c0(x1) |
(21) |
1.1.1 Rule Removal
Using the
matrix interpretations of dimension 1 with strict dimension 1 over the rationals with delta = 1
[c0(x1)] |
= |
x1 +
|
[c1(x1)] |
= |
x1 +
|
[a0(x1)] |
= |
x1 +
|
[a1(x1)] |
= |
x1 +
|
all of the following rules can be deleted.
a1(a1(a1(a1(x1)))) |
→ |
a1(a0(c1(a1(a1(x1))))) |
(10) |
a1(a1(a1(a0(x1)))) |
→ |
a1(a0(c1(a1(a0(x1))))) |
(11) |
c1(a1(a1(a1(x1)))) |
→ |
c1(a0(c1(a1(a1(x1))))) |
(12) |
c1(a1(a1(a0(x1)))) |
→ |
c1(a0(c1(a1(a0(x1))))) |
(13) |
a0(c0(c0(c1(x1)))) |
→ |
a1(a1(x1)) |
(14) |
a0(c0(c0(c0(x1)))) |
→ |
a1(a0(x1)) |
(15) |
c0(c0(c0(c1(x1)))) |
→ |
c1(a1(x1)) |
(16) |
c0(c0(c0(c0(x1)))) |
→ |
c1(a0(x1)) |
(17) |
a1(a1(x1)) |
→ |
a1(x1) |
(18) |
a1(a0(x1)) |
→ |
a0(x1) |
(19) |
c1(a1(x1)) |
→ |
c1(x1) |
(20) |
c1(a0(x1)) |
→ |
c0(x1) |
(21) |
1.1.1.1 R is empty
There are no rules in the TRS. Hence, it is terminating.