The rewrite relation of the following TRS is considered.
b(a(b(b(a(b(b(a(b(a(x1)))))))))) | → | a(b(a(b(b(a(b(b(a(b(b(a(x1)))))))))))) | (1) |
a(b(a(b(b(a(b(b(a(b(x1)))))))))) | → | a(b(b(a(b(b(a(b(b(a(b(a(x1)))))))))))) | (2) |
a#(b(a(b(b(a(b(b(a(b(x1)))))))))) | → | a#(x1) | (3) |
a#(b(a(b(b(a(b(b(a(b(x1)))))))))) | → | a#(b(b(a(b(b(a(b(b(a(b(a(x1)))))))))))) | (4) |
a#(b(a(b(b(a(b(b(a(b(x1)))))))))) | → | a#(b(b(a(b(b(a(b(a(x1))))))))) | (5) |
a#(b(a(b(b(a(b(b(a(b(x1)))))))))) | → | a#(b(b(a(b(a(x1)))))) | (6) |
a#(b(a(b(b(a(b(b(a(b(x1)))))))))) | → | a#(b(a(x1))) | (7) |
The dependency pairs are split into 1 component.
a#(b(a(b(b(a(b(b(a(b(x1)))))))))) | → | a#(x1) | (3) |
a#(b(a(b(b(a(b(b(a(b(x1)))))))))) | → | a#(b(a(x1))) | (7) |
[b(x1)] | = |
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[a(x1)] | = |
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[a#(x1)] | = |
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a(b(a(b(b(a(b(b(a(b(x1)))))))))) | → | a(b(b(a(b(b(a(b(b(a(b(a(x1)))))))))))) | (2) |
a#(b(a(b(b(a(b(b(a(b(x1)))))))))) | → | a#(x1) | (3) |
The dependency pairs are split into 1 component.
a#(b(a(b(b(a(b(b(a(b(x1)))))))))) | → | a#(b(a(x1))) | (7) |
[b(x1)] | = |
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[a(x1)] | = |
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[a#(x1)] | = |
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a(b(a(b(b(a(b(b(a(b(x1)))))))))) | → | a(b(b(a(b(b(a(b(b(a(b(a(x1)))))))))))) | (2) |
a#(b(a(b(b(a(b(b(a(b(x1)))))))))) | → | a#(b(a(x1))) | (7) |
The dependency pairs are split into 0 components.