Certification Problem
Input (TPDB SRS_Standard/Zantema_04/z012)
The rewrite relation of the following TRS is considered.
a(x1) |
→ |
b(x1) |
(1) |
a(b(x1)) |
→ |
b(c(a(x1))) |
(2) |
b(x1) |
→ |
c(x1) |
(3) |
c(b(x1)) |
→ |
a(x1) |
(4) |
Property / Task
Prove or disprove termination.Answer / Result
Yes.Proof (by matchbox @ termCOMP 2023)
1 Rule Removal
Using the
matrix interpretations of dimension 1 with strict dimension 1 over the rationals with delta = 1
[c(x1)] |
= |
x1 +
|
[b(x1)] |
= |
x1 +
|
[a(x1)] |
= |
x1 +
|
all of the following rules can be deleted.
1.1 Dependency Pair Transformation
The following set of initial dependency pairs has been identified.
c#(b(x1)) |
→ |
a#(x1) |
(5) |
a#(b(x1)) |
→ |
c#(a(x1)) |
(6) |
a#(b(x1)) |
→ |
a#(x1) |
(7) |
1.1.1 Monotonic Reduction Pair Processor with Usable Rules
Using the matrix interpretations of dimension 1 with strict dimension 1 over the rationals with delta = 1
[c(x1)] |
= |
x1 +
|
[b(x1)] |
= |
x1 +
|
[a(x1)] |
= |
x1 +
|
[c#(x1)] |
= |
x1 +
|
[a#(x1)] |
= |
x1 +
|
together with the usable
rules
a(x1) |
→ |
b(x1) |
(1) |
a(b(x1)) |
→ |
b(c(a(x1))) |
(2) |
c(b(x1)) |
→ |
a(x1) |
(4) |
(w.r.t. the implicit argument filter of the reduction pair),
the
pairs
c#(b(x1)) |
→ |
a#(x1) |
(5) |
a#(b(x1)) |
→ |
c#(a(x1)) |
(6) |
a#(b(x1)) |
→ |
a#(x1) |
(7) |
and
no rules
could be deleted.
1.1.1.1 Dependency Graph Processor
The dependency pairs are split into 0
components.