Certification Problem

Input (TPDB SRS_Standard/Zantema_04/z118)

The rewrite relation of the following TRS is considered.

a(x1) g(d(x1)) (1)
b(b(b(x1))) c(d(c(x1))) (2)
b(b(x1)) a(g(g(x1))) (3)
c(d(x1)) g(g(x1)) (4)
g(g(g(x1))) b(b(x1)) (5)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by matchbox @ termCOMP 2023)

1 Rule Removal

Using the matrix interpretations of dimension 1 with strict dimension 1 over the rationals with delta = 1
[g(x1)] = x1 +
6
[d(x1)] = x1 +
0
[c(x1)] = x1 +
13
[b(x1)] = x1 +
9
[a(x1)] = x1 +
6
all of the following rules can be deleted.
b(b(b(x1))) c(d(c(x1))) (2)
c(d(x1)) g(g(x1)) (4)

1.1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
g#(g(g(x1))) b#(x1) (6)
g#(g(g(x1))) b#(b(x1)) (7)
b#(b(x1)) g#(x1) (8)
b#(b(x1)) g#(g(x1)) (9)
b#(b(x1)) a#(g(g(x1))) (10)
a#(x1) g#(d(x1)) (11)

1.1.1 Monotonic Reduction Pair Processor with Usable Rules

Using the matrix interpretations of dimension 1 with strict dimension 1 over the rationals with delta = 1
[g(x1)] = x1 +
2/3
[d(x1)] = x1 +
0
[b(x1)] = x1 +
1
[a(x1)] = x1 +
2/3
[g#(x1)] = x1 +
0
[b#(x1)] = x1 +
1/3
[a#(x1)] = x1 +
0
together with the usable rules
a(x1) g(d(x1)) (1)
b(b(x1)) a(g(g(x1))) (3)
g(g(g(x1))) b(b(x1)) (5)
(w.r.t. the implicit argument filter of the reduction pair), the pairs
g#(g(g(x1))) b#(x1) (6)
b#(b(x1)) g#(x1) (8)
b#(b(x1)) g#(g(x1)) (9)
and no rules could be deleted.

1.1.1.1 Dependency Graph Processor

The dependency pairs are split into 0 components.