Certification Problem

Input (TPDB SRS_Standard/Wenzel_16/aabaaaa-aaaaaabaabaab.srs)

The rewrite relation of the following TRS is considered.

a(a(b(a(a(a(a(x1))))))) a(a(a(a(a(a(b(a(a(b(a(a(b(x1))))))))))))) (1)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by ttt2 @ termCOMP 2023)

1 Semantic Labeling

Root-labeling is applied.

We obtain the labeled TRS
aa(ab(ba(aa(aa(aa(aa(x1))))))) aa(aa(aa(aa(aa(ab(ba(aa(ab(ba(aa(ab(ba(x1))))))))))))) (2)
aa(ab(ba(aa(aa(aa(ab(x1))))))) aa(aa(aa(aa(aa(ab(ba(aa(ab(ba(aa(ab(bb(x1))))))))))))) (3)

1.1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
aa#(ab(ba(aa(aa(aa(aa(x1))))))) aa#(ab(ba(x1))) (4)
aa#(ab(ba(aa(aa(aa(aa(x1))))))) aa#(ab(ba(aa(ab(ba(x1)))))) (5)
aa#(ab(ba(aa(aa(aa(aa(x1))))))) aa#(ab(ba(aa(ab(ba(aa(ab(ba(x1))))))))) (6)
aa#(ab(ba(aa(aa(aa(aa(x1))))))) aa#(aa(ab(ba(aa(ab(ba(aa(ab(ba(x1)))))))))) (7)
aa#(ab(ba(aa(aa(aa(aa(x1))))))) aa#(aa(aa(ab(ba(aa(ab(ba(aa(ab(ba(x1))))))))))) (8)
aa#(ab(ba(aa(aa(aa(aa(x1))))))) aa#(aa(aa(aa(ab(ba(aa(ab(ba(aa(ab(ba(x1)))))))))))) (9)
aa#(ab(ba(aa(aa(aa(aa(x1))))))) aa#(aa(aa(aa(aa(ab(ba(aa(ab(ba(aa(ab(ba(x1))))))))))))) (10)
aa#(ab(ba(aa(aa(aa(ab(x1))))))) aa#(ab(bb(x1))) (11)
aa#(ab(ba(aa(aa(aa(ab(x1))))))) aa#(ab(ba(aa(ab(bb(x1)))))) (12)
aa#(ab(ba(aa(aa(aa(ab(x1))))))) aa#(ab(ba(aa(ab(ba(aa(ab(bb(x1))))))))) (13)
aa#(ab(ba(aa(aa(aa(ab(x1))))))) aa#(aa(ab(ba(aa(ab(ba(aa(ab(bb(x1)))))))))) (14)
aa#(ab(ba(aa(aa(aa(ab(x1))))))) aa#(aa(aa(ab(ba(aa(ab(ba(aa(ab(bb(x1))))))))))) (15)
aa#(ab(ba(aa(aa(aa(ab(x1))))))) aa#(aa(aa(aa(ab(ba(aa(ab(ba(aa(ab(bb(x1)))))))))))) (16)
aa#(ab(ba(aa(aa(aa(ab(x1))))))) aa#(aa(aa(aa(aa(ab(ba(aa(ab(ba(aa(ab(bb(x1))))))))))))) (17)

1.1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.