Certification Problem
Input (TPDB TRS_Outermost/Strategy_outermost_added_08/test9)
The rewrite relation of the following TRS is considered.
f(0,1,X) |
→ |
h(X,X) |
(1) |
h(0,X) |
→ |
f(0,X,X) |
(2) |
g(X,Y) |
→ |
X |
(3) |
g(X,Y) |
→ |
Y |
(4) |
The evaluation strategy is outermostProperty / Task
Prove or disprove termination.Answer / Result
No.Proof (by AProVE @ termCOMP 2023)
1 Loop
The following loop proves nontermination.
t0
|
= |
h(g(1,0),g(1,0)) |
|
→
|
h(0,g(1,0)) |
|
→
|
f(0,g(1,0),g(1,0)) |
|
→
|
f(0,1,g(1,0)) |
|
→
|
h(g(1,0),g(1,0)) |
|
= |
t4
|
where t4 =
t0