Certification Problem

Input (TPDB TRS_Standard/AG01/#3.23)

The rewrite relation of the following TRS is considered.

f(0,y) 0 (1)
f(s(x),y) f(f(x,y),y) (2)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by AProVE @ termCOMP 2023)

1 Switch to Innermost Termination

The TRS is overlay and locally confluent:

10

Hence, it suffices to show innermost termination in the following.

1.1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
f#(s(x),y) f#(f(x,y),y) (3)
f#(s(x),y) f#(x,y) (4)

1.1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.