The rewrite relation of the following TRS is considered.
g(a) | → | g(b) | (1) |
b | → | f(a,a) | (2) |
f(a,a) | → | g(d) | (3) |
The TRS is overlay and locally confluent:
10Hence, it suffices to show innermost termination in the following.
g#(a) | → | g#(b) | (4) |
g#(a) | → | b# | (5) |
b# | → | f#(a,a) | (6) |
f#(a,a) | → | g#(d) | (7) |
The dependency pairs are split into 0 components.