Certification Problem
Input (TPDB TRS_Standard/AG01/#3.49)
The rewrite relation of the following TRS is considered.
f(c(s(x),y)) |
→ |
f(c(x,s(y))) |
(1) |
f(c(s(x),s(y))) |
→ |
g(c(x,y)) |
(2) |
g(c(x,s(y))) |
→ |
g(c(s(x),y)) |
(3) |
g(c(s(x),s(y))) |
→ |
f(c(x,y)) |
(4) |
Property / Task
Prove or disprove termination.Answer / Result
Yes.Proof (by NaTT @ termCOMP 2023)
1 Dependency Pair Transformation
The following set of initial dependency pairs has been identified.
g#(c(x,s(y))) |
→ |
g#(c(s(x),y)) |
(5) |
f#(c(s(x),y)) |
→ |
f#(c(x,s(y))) |
(6) |
f#(c(s(x),s(y))) |
→ |
g#(c(x,y)) |
(7) |
g#(c(s(x),s(y))) |
→ |
f#(c(x,y)) |
(8) |
1.1 Dependency Graph Processor
The dependency pairs are split into 1
component.