The rewrite relation of the following TRS is considered.
g(0) | → | 0 | (1) |
g(s(x)) | → | f(g(x)) | (2) |
f(0) | → | 0 | (3) |
g#(s(x)) | → | g#(x) | (4) |
g#(s(x)) | → | f#(g(x)) | (5) |
The dependency pairs are split into 1 component.
g#(s(x)) | → | g#(x) | (4) |
[s(x1)] | = | x1 + 1 |
[f(x1)] | = | 0 |
[0] | = | 0 |
[f#(x1)] | = | 0 |
[g#(x1)] | = | x1 + 0 |
[g(x1)] | = | 0 |
g#(s(x)) | → | g#(x) | (4) |
The dependency pairs are split into 0 components.