Certification Problem

Input (TPDB TRS_Standard/SK90/4.32)

The rewrite relation of the following TRS is considered.

a(b(x)) b(a(a(x))) (1)
b(c(x)) c(b(b(x))) (2)
c(a(x)) a(c(c(x))) (3)
u(a(x)) x (4)
v(b(x)) x (5)
w(c(x)) x (6)
a(u(x)) x (7)
b(v(x)) x (8)
c(w(x)) x (9)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by NaTT @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
b#(c(x)) b#(b(x)) (10)
c#(a(x)) c#(x) (11)
a#(b(x)) a#(x) (12)
a#(b(x)) b#(a(a(x))) (13)
c#(a(x)) c#(c(x)) (14)
b#(c(x)) b#(x) (15)
b#(c(x)) c#(b(b(x))) (16)
a#(b(x)) a#(a(x)) (17)
c#(a(x)) a#(c(c(x))) (18)

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.