The rewrite relation of the following TRS is considered.
f(a,y) | → | f(y,g(y)) | (1) |
g(a) | → | b | (2) |
g(b) | → | b | (3) |
f#(a,y) | → | g#(y) | (4) |
f#(a,y) | → | f#(y,g(y)) | (5) |
The dependency pairs are split into 1 component.
f#(a,y) | → | f#(y,g(y)) | (5) |
[a] | = | 2 |
[b] | = | 1 |
[f(x1, x2)] | = | 0 |
[f#(x1, x2)] | = | x1 + x2 + 0 |
[g#(x1)] | = | 0 |
[g(x1)] | = | 1 |
g(b) | → | b | (3) |
g(a) | → | b | (2) |
f#(a,y) | → | f#(y,g(y)) | (5) |
The dependency pairs are split into 0 components.