LTS Termination Proof

by AProVE

Input

Integer Transition System

Proof

1 Switch to Cooperation Termination Proof

We consider the following cutpoint-transitions:
f795_0_main_GE f795_0_main_GE f795_0_main_GE: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6x7 = x7x8 = x8
f1421_0_sort_GE f1421_0_sort_GE f1421_0_sort_GE: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6x7 = x7x8 = x8
f1445_0_aux_LT f1445_0_aux_LT f1445_0_aux_LT: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6x7 = x7x8 = x8
f1_0_main_Load f1_0_main_Load f1_0_main_Load: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6x7 = x7x8 = x8
f1611_0_aux_InvokeMethod f1611_0_aux_InvokeMethod f1611_0_aux_InvokeMethod: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6x7 = x7x8 = x8
__init __init __init: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6x7 = x7x8 = x8
and for every transition t, a duplicate t is considered.

2 SCC Decomposition

We consider subproblems for each of the 3 SCC(s) of the program graph.

2.1 SCC Subproblem 1/3

Here we consider the SCC { f795_0_main_GE }.

2.1.1 Transition Removal

We remove transitions 4, 5 using the following ranking functions, which are bounded by 0.

f795_0_main_GE: x3 + x4

2.1.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.2 SCC Subproblem 2/3

Here we consider the SCC { f1421_0_sort_GE }.

2.2.1 Transition Removal

We remove transition 8 using the following ranking functions, which are bounded by 0.

f1421_0_sort_GE: −1 − x3 + x4

2.2.2 Transition Removal

We remove transition 7 using the following ranking functions, which are bounded by 0.

f1421_0_sort_GE: x3 + x4

2.2.3 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.3 SCC Subproblem 3/3

Here we consider the SCC { f1445_0_aux_LT, f1611_0_aux_InvokeMethod }.

2.3.1 Transition Removal

We remove transitions 10, 12, 11 using the following ranking functions, which are bounded by 0.

f1445_0_aux_LT: −1 − 2⋅x2 + 2⋅x5
f1611_0_aux_InvokeMethod: −2⋅x2 + 2⋅x3

2.3.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

Tool configuration

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