LTS Termination Proof

by AProVE

Input

Integer Transition System

Proof

1 Switch to Cooperation Termination Proof

We consider the following cutpoint-transitions:
f361_0_fractale_LE f361_0_fractale_LE f361_0_fractale_LE: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6x7 = x7x8 = x8
f361_0_fractale_LE' f361_0_fractale_LE' f361_0_fractale_LE': x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6x7 = x7x8 = x8
f425_0_fractale_InvokeMethod f425_0_fractale_InvokeMethod f425_0_fractale_InvokeMethod: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6x7 = x7x8 = x8
f1_0_main_Load f1_0_main_Load f1_0_main_Load: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6x7 = x7x8 = x8
__init __init __init: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6x7 = x7x8 = x8
and for every transition t, a duplicate t is considered.

2 SCC Decomposition

We consider subproblems for each of the 1 SCC(s) of the program graph.

2.1 SCC Subproblem 1/1

Here we consider the SCC { f361_0_fractale_LE, f361_0_fractale_LE', f425_0_fractale_InvokeMethod }.

2.1.1 Transition Removal

We remove transitions 2, 3, 4, 8, 7, 5, 6 using the following ranking functions, which are bounded by 0.

f361_0_fractale_LE: 2 + 3⋅x3
f361_0_fractale_LE': 1 + 3⋅x3
f425_0_fractale_InvokeMethod: 3⋅x1

2.1.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

Tool configuration

AProVE