LTS Termination Proof

by AProVE

Input

Integer Transition System

Proof

1 Switch to Cooperation Termination Proof

We consider the following cutpoint-transitions:
f218_0_test_LE f218_0_test_LE f218_0_test_LE: x1 = x1x2 = x2x3 = x3
f134_0_test_LE f134_0_test_LE f134_0_test_LE: x1 = x1x2 = x2x3 = x3
f162_0_test_LE f162_0_test_LE f162_0_test_LE: x1 = x1x2 = x2x3 = x3
f176_0_test_LE f176_0_test_LE f176_0_test_LE: x1 = x1x2 = x2x3 = x3
__init __init __init: x1 = x1x2 = x2x3 = x3
f92_0_test_LE f92_0_test_LE f92_0_test_LE: x1 = x1x2 = x2x3 = x3
f148_0_test_LE f148_0_test_LE f148_0_test_LE: x1 = x1x2 = x2x3 = x3
f190_0_test_LE f190_0_test_LE f190_0_test_LE: x1 = x1x2 = x2x3 = x3
f31_0_main_Cmp f31_0_main_Cmp f31_0_main_Cmp: x1 = x1x2 = x2x3 = x3
f43_0_main_GE f43_0_main_GE f43_0_main_GE: x1 = x1x2 = x2x3 = x3
f78_0_test_LE f78_0_test_LE f78_0_test_LE: x1 = x1x2 = x2x3 = x3
f120_0_test_LE f120_0_test_LE f120_0_test_LE: x1 = x1x2 = x2x3 = x3
f1_0_main_Load f1_0_main_Load f1_0_main_Load: x1 = x1x2 = x2x3 = x3
f106_0_test_LE f106_0_test_LE f106_0_test_LE: x1 = x1x2 = x2x3 = x3
f64_0_test_LE f64_0_test_LE f64_0_test_LE: x1 = x1x2 = x2x3 = x3
f204_0_test_LE f204_0_test_LE f204_0_test_LE: x1 = x1x2 = x2x3 = x3
and for every transition t, a duplicate t is considered.

2 SCC Decomposition

We consider subproblems for each of the 13 SCC(s) of the program graph.

2.1 SCC Subproblem 1/13

Here we consider the SCC { f31_0_main_Cmp, f43_0_main_GE }.

2.1.1 Transition Removal

We remove transition 3 using the following ranking functions, which are bounded by 0.

f31_0_main_Cmp: −1 + x1
f43_0_main_GE: −1 + x1

2.1.2 Transition Removal

We remove transition 4 using the following ranking functions, which are bounded by 0.

f31_0_main_Cmp: 99 − x1
f43_0_main_GE: 99 − x2

2.1.3 Transition Removal

We remove transition 2 using the following ranking functions, which are bounded by 0.

f31_0_main_Cmp: 0
f43_0_main_GE: −1

2.1.4 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.2 SCC Subproblem 2/13

Here we consider the SCC { f64_0_test_LE }.

2.2.1 Transition Removal

We remove transition 6 using the following ranking functions, which are bounded by 0.

f64_0_test_LE: x3

2.2.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.3 SCC Subproblem 3/13

Here we consider the SCC { f78_0_test_LE }.

2.3.1 Transition Removal

We remove transition 8 using the following ranking functions, which are bounded by 0.

f78_0_test_LE: x3

2.3.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.4 SCC Subproblem 4/13

Here we consider the SCC { f92_0_test_LE }.

2.4.1 Transition Removal

We remove transition 10 using the following ranking functions, which are bounded by 0.

f92_0_test_LE: x3

2.4.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.5 SCC Subproblem 5/13

Here we consider the SCC { f106_0_test_LE }.

2.5.1 Transition Removal

We remove transition 12 using the following ranking functions, which are bounded by 0.

f106_0_test_LE: x3

2.5.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.6 SCC Subproblem 6/13

Here we consider the SCC { f120_0_test_LE }.

2.6.1 Transition Removal

We remove transition 14 using the following ranking functions, which are bounded by 0.

f120_0_test_LE: x3

2.6.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.7 SCC Subproblem 7/13

Here we consider the SCC { f134_0_test_LE }.

2.7.1 Transition Removal

We remove transition 16 using the following ranking functions, which are bounded by 0.

f134_0_test_LE: x3

2.7.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.8 SCC Subproblem 8/13

Here we consider the SCC { f148_0_test_LE }.

2.8.1 Transition Removal

We remove transition 18 using the following ranking functions, which are bounded by 0.

f148_0_test_LE: x3

2.8.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.9 SCC Subproblem 9/13

Here we consider the SCC { f162_0_test_LE }.

2.9.1 Transition Removal

We remove transition 20 using the following ranking functions, which are bounded by 0.

f162_0_test_LE: x3

2.9.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.10 SCC Subproblem 10/13

Here we consider the SCC { f176_0_test_LE }.

2.10.1 Transition Removal

We remove transition 22 using the following ranking functions, which are bounded by 0.

f176_0_test_LE: x3

2.10.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.11 SCC Subproblem 11/13

Here we consider the SCC { f190_0_test_LE }.

2.11.1 Transition Removal

We remove transition 24 using the following ranking functions, which are bounded by 0.

f190_0_test_LE: x3

2.11.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.12 SCC Subproblem 12/13

Here we consider the SCC { f204_0_test_LE }.

2.12.1 Transition Removal

We remove transition 26 using the following ranking functions, which are bounded by 0.

f204_0_test_LE: x3

2.12.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.13 SCC Subproblem 13/13

Here we consider the SCC { f218_0_test_LE }.

2.13.1 Transition Removal

We remove transition 28 using the following ranking functions, which are bounded by 0.

f218_0_test_LE: x1

2.13.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

Tool configuration

AProVE