3.17/1.65	YES
3.17/1.65	
3.17/1.65	Proof:
3.17/1.65	This system is confluent.
3.17/1.65	By \cite{ALS94}, Theorem 4.1.
3.17/1.65	This system is of type 3 or smaller.
3.17/1.65	This system is strongly deterministic.
3.17/1.65	This system is quasi-decreasing.
3.17/1.65	By \cite{O02}, p. 214, Proposition 7.2.50.
3.17/1.65	This system is of type 3 or smaller.
3.17/1.65	This system is deterministic.
3.17/1.65	System R transformed to U(R).
3.17/1.65	This system is terminating.
3.17/1.65	Call external tool:
3.17/1.65	./ttt2.sh
3.17/1.65	Input:
3.17/1.65	(VAR y x)
3.17/1.65	(RULES
3.17/1.65	  ?1(y, x) -> g(y)
3.17/1.65	  f(x) -> ?1(x, x)
3.17/1.65	  a -> c
3.17/1.65	  b -> c
3.17/1.65	)
3.17/1.65	
3.17/1.65	 Polynomial Interpretation Processor:
3.17/1.65	  dimension: 1
3.17/1.65	  interpretation:
3.17/1.65	   [b] = 1,
3.17/1.65	   
3.17/1.65	   [c] = 0,
3.17/1.65	   
3.17/1.65	   [a] = 1,
3.17/1.65	   
3.17/1.65	   [f](x0) = 6x0 + 5x0x0 + 4,
3.17/1.65	   
3.17/1.65	   [g](x0) = -3x0 + 4x0x0,
3.17/1.65	   
3.17/1.65	   [?1](x0, x1) = 6x1 + 4x0x0 + x1x1 + 1
3.17/1.65	  orientation:
3.17/1.65	   ?1(y,x) = 6x + x*x + 4y*y + 1 >= -3y + 4y*y = g(y)
3.17/1.65	   
3.17/1.65	   f(x) = 6x + 5x*x + 4 >= 6x + 5x*x + 1 = ?1(x,x)
3.17/1.65	   
3.17/1.65	   a() = 1 >= 0 = c()
3.17/1.65	   
3.17/1.65	   b() = 1 >= 0 = c()
3.17/1.65	  problem:
3.17/1.65	   
3.17/1.65	  Qed
3.17/1.65	All 0 critical pairs are joinable.
3.17/1.65	
3.17/1.68	EOF