1.66/1.28	MAYBE
1.66/1.28	
1.66/1.28	Proof:
1.66/1.28	ConCon could not decide confluence of the system.
1.66/1.28	\cite{ALS94}, Theorem 4.1 does not apply.
1.66/1.28	This system is of type 3 or smaller.
1.66/1.28	This system is strongly deterministic.
1.66/1.28	This system is quasi-decreasing.
1.66/1.28	By \cite{A14}, Theorem 11.5.9.
1.66/1.28	This system is of type 3 or smaller.
1.66/1.28	This system is deterministic.
1.66/1.28	System R transformed to V(R) + Emb.
1.66/1.28	This system is terminating.
1.66/1.28	Call external tool:
1.66/1.28	./ttt2.sh
1.66/1.28	Input:
1.66/1.28	  a -> t(c)
1.66/1.28	  a -> t(d)
1.66/1.28	  f(x, y) -> x
1.66/1.28	  g(x, x) -> h(x, x)
1.66/1.28	  h(x, y) -> x
1.66/1.28	  h(x, y) -> y
1.66/1.28	  g(x, y) -> x
1.66/1.28	  g(x, y) -> y
1.66/1.28	  t(x) -> x
1.66/1.28	  f(x, y) -> x
1.66/1.28	  f(x, y) -> y
1.66/1.28	
1.66/1.28	 Polynomial Interpretation Processor:
1.66/1.28	  dimension: 1
1.66/1.28	  interpretation:
1.66/1.28	   [h](x0, x1) = 2x0 + x1 + 4,
1.66/1.28	   
1.66/1.28	   [g](x0, x1) = x0 + 2x1 + 5,
1.66/1.28	   
1.66/1.28	   [f](x0, x1) = x0 + x1 + 7x1x1 + 4,
1.66/1.28	   
1.66/1.28	   [d] = 0,
1.66/1.28	   
1.66/1.28	   [t](x0) = 4x0 + 4,
1.66/1.28	   
1.66/1.28	   [c] = 0,
1.66/1.28	   
1.66/1.28	   [a] = 5
1.66/1.28	  orientation:
1.66/1.28	   a() = 5 >= 4 = t(c())
2.95/1.28	   
2.95/1.28	   a() = 5 >= 4 = t(d())
2.95/1.28	   
2.95/1.28	   f(x,y) = x + y + 7y*y + 4 >= x = x
2.95/1.28	   
2.95/1.28	   g(x,x) = 3x + 5 >= 3x + 4 = h(x,x)
2.95/1.29	   
2.95/1.29	   h(x,y) = 2x + y + 4 >= x = x
2.95/1.29	   
2.95/1.29	   h(x,y) = 2x + y + 4 >= y = y
2.95/1.29	   
2.95/1.29	   g(x,y) = x + 2y + 5 >= x = x
2.95/1.29	   
2.95/1.29	   g(x,y) = x + 2y + 5 >= y = y
2.95/1.29	   
2.95/1.29	   t(x) = 4x + 4 >= x = x
2.95/1.29	   
2.95/1.29	   f(x,y) = x + y + 7y*y + 4 >= y = y
2.95/1.29	  problem:
2.95/1.29	   
2.95/1.29	  Qed
2.95/1.29	This critical pair is not infeasible.
2.95/1.29	This critical pair is unconditional.
2.95/1.29	
2.95/1.32	EOF