1.97/1.17	YES
1.97/1.17	
1.97/1.17	Proof:
1.97/1.17	This system is confluent.
1.97/1.17	By \cite{ALS94}, Theorem 4.1.
1.97/1.17	This system is of type 3 or smaller.
1.97/1.17	This system is strongly deterministic.
1.97/1.17	This system is quasi-decreasing.
1.97/1.17	By \cite{O02}, p. 214, Proposition 7.2.50.
1.97/1.17	This system is of type 3 or smaller.
1.97/1.17	This system is deterministic.
1.97/1.17	System R transformed to optimized U(R).
1.97/1.17	This system is terminating.
1.97/1.17	Call external tool:
1.97/1.17	./ttt2.sh
1.97/1.17	Input:
1.97/1.17	  a -> b
1.97/1.17	  f(x) -> ?1(x, x)
1.97/1.17	  ?1(b, x) -> A
1.97/1.17	  g(x, x) -> h(x)
1.97/1.17	  h(x) -> i(x)
1.97/1.17	
1.97/1.17	 Polynomial Interpretation Processor:
1.97/1.17	  dimension: 1
1.97/1.17	  interpretation:
1.97/1.17	   [i](x0) = -3x0 + 4x0x0,
1.97/1.17	   
1.97/1.17	   [h](x0) = 4x0x0 + 1,
1.97/1.17	   
1.97/1.17	   [g](x0, x1) = 4x0 + 5x1x1 + 4,
1.97/1.17	   
1.97/1.17	   [A] = 0,
1.97/1.17	   
1.97/1.17	   [?1](x0, x1) = -1x0 + 2x0x0 + x1x1 + 4,
1.97/1.17	   
1.97/1.17	   [f](x0) = 3x0x0 + 5,
1.97/1.17	   
1.97/1.17	   [b] = 0,
2.39/1.17	   
2.39/1.17	   [a] = 1
2.39/1.17	  orientation:
2.39/1.17	   a() = 1 >= 0 = b()
2.39/1.17	   
2.39/1.17	   f(x) = 3x*x + 5 >= -1x + 3x*x + 4 = ?1(x,x)
2.39/1.17	   
2.39/1.17	   ?1(b(),x) = x*x + 4 >= 0 = A()
2.39/1.17	   
2.39/1.17	   g(x,x) = 4x + 5x*x + 4 >= 4x*x + 1 = h(x)
2.39/1.17	   
2.39/1.17	   h(x) = 4x*x + 1 >= -3x + 4x*x = i(x)
2.39/1.17	  problem:
2.39/1.17	   
2.39/1.17	  Qed
2.39/1.17	All 0 critical pairs are joinable.
2.39/1.17	
2.39/1.20	EOF