3.29/1.40	MAYBE
3.29/1.40	
3.29/1.40	Proof:
3.29/1.40	ConCon could not decide confluence of the system.
3.29/1.40	\cite{ALS94}, Theorem 4.1 does not apply.
3.29/1.40	This system is of type 3 or smaller.
3.29/1.40	This system is strongly deterministic.
3.29/1.40	This system is quasi-decreasing.
3.29/1.40	By \cite{A14}, Theorem 11.5.9.
3.29/1.40	This system is of type 3 or smaller.
3.29/1.40	This system is deterministic.
3.29/1.40	System R transformed to V(R) + Emb.
3.29/1.40	This system is terminating.
3.29/1.40	Call external tool:
3.29/1.40	./ttt2.sh
3.29/1.40	Input:
3.29/1.40	  s(a) -> c
3.29/1.40	  s(b) -> c
3.29/1.40	  c -> t(k)
3.29/1.40	  c -> t(l)
3.29/1.40	  f(x) -> s(x)
3.29/1.40	  g(x, x) -> h(x, x)
3.29/1.40	  h(x, y) -> x
3.29/1.40	  h(x, y) -> y
3.29/1.40	  s(x) -> x
3.29/1.40	  g(x, y) -> x
3.29/1.40	  g(x, y) -> y
3.29/1.40	  t(x) -> x
3.29/1.40	  f(x) -> x
3.29/1.40	
3.29/1.40	 Polynomial Interpretation Processor:
3.29/1.40	  dimension: 1
3.29/1.40	  interpretation:
3.29/1.40	   [h](x0, x1) = x0 + 2x1 + 2,
3.29/1.40	   
3.29/1.40	   [g](x0, x1) = 4x0 + 4x1 + 5,
3.29/1.40	   
3.29/1.40	   [f](x0) = 4x0 + 5,
3.29/1.40	   
3.29/1.40	   [l] = 0,
3.29/1.40	   
3.29/1.40	   [t](x0) = 4x0 + 4,
3.29/1.40	   
3.29/1.40	   [k] = 0,
3.29/1.40	   
3.29/1.40	   [b] = 2,
3.29/1.40	   
3.29/1.40	   [c] = 5,
3.29/1.40	   
3.29/1.40	   [s](x0) = 2x0 + 4,
3.29/1.40	   
3.29/1.40	   [a] = 4
3.29/1.40	  orientation:
3.29/1.40	   s(a()) = 12 >= 5 = c()
3.29/1.40	   
3.29/1.40	   s(b()) = 8 >= 5 = c()
3.29/1.40	   
3.29/1.40	   c() = 5 >= 4 = t(k())
3.29/1.40	   
3.29/1.40	   c() = 5 >= 4 = t(l())
3.29/1.40	   
3.29/1.40	   f(x) = 4x + 5 >= 2x + 4 = s(x)
3.29/1.40	   
3.29/1.40	   g(x,x) = 8x + 5 >= 3x + 2 = h(x,x)
3.29/1.40	   
3.29/1.40	   h(x,y) = x + 2y + 2 >= x = x
3.29/1.40	   
3.29/1.40	   h(x,y) = x + 2y + 2 >= y = y
3.29/1.40	   
3.29/1.40	   s(x) = 2x + 4 >= x = x
3.29/1.40	   
3.29/1.40	   g(x,y) = 4x + 4y + 5 >= x = x
3.29/1.40	   
3.29/1.40	   g(x,y) = 4x + 4y + 5 >= y = y
3.29/1.40	   
3.29/1.40	   t(x) = 4x + 4 >= x = x
3.29/1.40	   
3.29/1.40	   f(x) = 4x + 5 >= x = x
3.29/1.40	  problem:
3.29/1.40	   
3.29/1.40	  Qed
3.29/1.40	This critical pair is not joinable.
3.29/1.40	
3.60/1.47	EOF