2.81/1.23	MAYBE
2.81/1.23	
2.81/1.23	Proof:
2.81/1.23	ConCon could not decide confluence of the system.
2.81/1.23	\cite{ALS94}, Theorem 4.1 does not apply.
2.81/1.23	This system is of type 3 or smaller.
2.81/1.23	This system is strongly deterministic.
2.81/1.23	This system is quasi-decreasing.
2.81/1.23	By \cite{A14}, Theorem 11.5.9.
2.81/1.23	This system is of type 3 or smaller.
2.81/1.23	This system is deterministic.
2.81/1.23	System R transformed to V(R) + Emb.
2.81/1.23	This system is terminating.
2.81/1.24	Call external tool:
2.81/1.24	./ttt2.sh
2.81/1.24	Input:
2.81/1.24	  a -> c
2.81/1.24	  a -> d
2.81/1.24	  s(c) -> t(k)
2.81/1.24	  f(x) -> s(x)
2.81/1.24	  s(x) -> x
2.81/1.24	  t(x) -> x
2.81/1.24	  f(x) -> x
2.81/1.24	
2.81/1.24	 Polynomial Interpretation Processor:
2.81/1.24	  dimension: 1
2.81/1.24	  interpretation:
2.81/1.24	   [f](x0) = x0 + 3,
2.81/1.24	   
2.81/1.24	   [t](x0) = x0 + 1,
2.81/1.24	   
2.81/1.24	   [k] = 1,
2.81/1.24	   
2.81/1.24	   [s](x0) = x0 + 1,
2.81/1.24	   
2.81/1.24	   [d] = 0,
2.81/1.24	   
2.81/1.24	   [c] = 2,
2.81/1.24	   
2.81/1.24	   [a] = 4
2.81/1.24	  orientation:
2.81/1.24	   a() = 4 >= 2 = c()
2.81/1.24	   
2.81/1.24	   a() = 4 >= 0 = d()
2.81/1.24	   
2.81/1.24	   s(c()) = 3 >= 2 = t(k())
2.81/1.24	   
2.81/1.24	   f(x) = x + 3 >= x + 1 = s(x)
2.81/1.24	   
2.81/1.24	   s(x) = x + 1 >= x = x
2.81/1.24	   
2.81/1.24	   t(x) = x + 1 >= x = x
2.81/1.24	   
2.81/1.24	   f(x) = x + 3 >= x = x
2.81/1.24	  problem:
2.81/1.24	   
2.81/1.24	  Qed
2.81/1.24	This critical pair is not trivial.
2.81/1.24	
2.81/1.26	EOF