Termination proof

1: switching to dependency pairs

The following set of initial dependency pairs has been identified.

average#( s( x ) , y ) average#( x , s( y ) )
average#( x , s( s( s( y ) ) ) ) average#( s( x ) , y )

1.1: reduction pair processor

Using the following reduction pair

Linear polynomial interpretation over the naturals
[average# (x1, x2) ] = x1 + x2
[s (x1) ] = x1 + 2
[0] = 0
[average (x1, x2) ] = x1 + x2 + 1
[f(x1, ..., xn)] = x1 + ... + xn + 1 for all other symbols f of arity n

one remains with the following pair(s).

average#( s( x ) , y ) average#( x , s( y ) )

1.1.1: reduction pair processor

Using the following reduction pair

Linear polynomial interpretation over the naturals
[average# (x1, x2) ] = x1
[s (x1) ] = x1 + 2
[0] = 3
[average (x1, x2) ] = 2 x1 + x2
[f(x1, ..., xn)] = x1 + ... + xn + 1 for all other symbols f of arity n

one remains with the following pair(s).

none

1.1.1.1: P is empty

All dependency pairs have been removed.