Certification Problem
Input (COPS 32)
We consider the TRS containing the following rules:
f(g(x),h(x)) |
→ |
a |
(1) |
g(b) |
→ |
d |
(2) |
h(c) |
→ |
d |
(3) |
The underlying signature is as follows:
{f/2, g/1, h/1, a/0, b/0, d/0, c/0}Property / Task
Prove or disprove confluence.Answer / Result
No.Proof (by csi @ CoCo 2021)
1 Non-Joinable Fork
The system is not confluent due to the following forking derivations.
t0
|
= |
f(g(c),h(c)) |
|
→
|
f(g(c),d) |
|
= |
t1
|
t0
|
= |
f(g(c),h(c)) |
|
→
|
a |
|
= |
t1
|
The two resulting terms cannot be joined for the following reason:
-
The reachable terms of these two terms are approximated via the following two tree automata,
and the tree automata have an empty intersection.
-
Automaton 1
-
final states:
{1}
-
transitions:
d |
→ |
2 |
c |
→ |
3 |
g(3) |
→ |
4 |
f(4,2) |
→ |
1 |
The automaton is closed under rewriting as it is state-compatible w.r.t. the following relation.
-
Automaton 2
-
final states:
{5}
-
transitions:
The automaton is closed under rewriting as it is state-compatible w.r.t. the following relation.