We consider the TRS containing the following rules:
f(a,f(x,a)) | → | f(a,f(f(a,a),a)) | (1) |
The underlying signature is as follows:
{f/2, a/0}To prove that the TRS is (non-)confluent, we show (non-)confluence of the following modified system:
f(a,f(x,a)) | → | f(a,f(f(a,a),a)) | (1) |
All redundant rules that were added or removed can be simulated in 2 steps .
Confluence is proven using the following terminating critical-pair-closing-system R:
There are no rules.
There are no rules in the TRS. Hence, it is terminating.