We consider the TRS containing the following rules:
a(b(a(a(a(a(a(a(a(a(a(x))))))))))) | → | a(a(a(a(a(a(a(a(a(a(a(b(a(b(x)))))))))))))) | (1) |
The underlying signature is as follows:
{a/1, b/1}t0 | = | a(b(a(a(a(a(a(a(a(a(a(b(a(a(a(a(a(a(a(a(a(x61))))))))))))))))))))) |
→ | a(b(a(a(a(a(a(a(a(a(a(a(a(a(a(a(a(a(a(a(a(b(a(b(x61)))))))))))))))))))))))) | |
→ | a(a(a(a(a(a(a(a(a(a(a(b(a(b(a(a(a(a(a(a(a(a(a(a(b(a(b(x61))))))))))))))))))))))))))) | |
→ | a(a(a(a(a(a(a(a(a(a(a(b(a(a(a(a(a(a(a(a(a(a(a(b(a(b(a(b(a(b(x61)))))))))))))))))))))))))))))) | |
→ | a(a(a(a(a(a(a(a(a(a(a(a(a(a(a(a(a(a(a(a(a(b(a(b(a(a(b(a(b(a(b(a(b(x61))))))))))))))))))))))))))))))))) | |
= | t4 |
t0 | = | a(b(a(a(a(a(a(a(a(a(a(b(a(a(a(a(a(a(a(a(a(x61))))))))))))))))))))) |
→ | a(a(a(a(a(a(a(a(a(a(a(b(a(b(b(a(a(a(a(a(a(a(a(a(x61)))))))))))))))))))))))) | |
= | t1 |