Certification Problem
Input (COPS 711)
We consider the TRS containing the following rules:
f(h(f(b),a)) |
→ |
b |
(1) |
f(c) |
→ |
b |
(2) |
b |
→ |
f(b) |
(3) |
The underlying signature is as follows:
{f/1, h/2, b/0, a/0, c/0}Property / Task
Prove or disprove confluence.Answer / Result
No.Proof (by csi @ CoCo 2022)
1 Non-Joinable Fork
The system is not confluent due to the following forking derivations.
t0
|
= |
f(h(f(b),a)) |
|
→
|
f(h(f(f(b)),a)) |
|
= |
t1
|
t0
|
= |
f(h(f(b),a)) |
|
→
|
b |
|
= |
t1
|
The two resulting terms cannot be joined for the following reason:
-
The reachable terms of these two terms are approximated via the following two tree automata,
and the tree automata have an empty intersection.
-
Automaton 1
-
final states:
{1}
-
transitions:
a |
→ |
2 |
f(3) |
→ |
4 |
f(3) |
→ |
3 |
f(6) |
→ |
1 |
f(4) |
→ |
5 |
b |
→ |
3 |
h(5,2) |
→ |
6 |
The automaton is closed under rewriting as it is compatible.
-
Automaton 2
-
final states:
{7}
-
transitions:
The automaton is closed under rewriting as it is compatible.