Certification Problem
Input (COPS 647)
We consider the TRS containing the following rules:
|
f(b) |
→ |
b |
(1) |
| b |
→ |
h(h(c,f(b)),a) |
(2) |
The underlying signature is as follows:
{f/1, b/0, h/2, c/0, a/0}Property / Task
Prove or disprove confluence.Answer / Result
No.Proof (by csi @ CoCo 2022)
1 Non-Joinable Fork
The system is not confluent due to the following forking derivations.
| t0
|
= |
f(b) |
|
→
|
f(h(h(c,f(b)),a)) |
|
= |
t1
|
The two resulting terms cannot be joined for the following reason:
-
The reachable terms of these two terms are approximated via the following two tree automata,
and the tree automata have an empty intersection.
-
Automaton 1
-
final states:
{1}
-
transitions:
| c |
→ |
5 |
| a |
→ |
2 |
|
f(3) |
→ |
4 |
|
f(7) |
→ |
1 |
| b |
→ |
3 |
| b |
→ |
4 |
|
h(5,4) |
→ |
6 |
|
h(6,2) |
→ |
7 |
|
h(6,2) |
→ |
3 |
|
h(6,2) |
→ |
4 |
The automaton is closed under rewriting as it is compatible.
-
Automaton 2
-
final states:
{8}
-
transitions:
| c |
→ |
13 |
| a |
→ |
11 |
|
f(8) |
→ |
12 |
| b |
→ |
8 |
| b |
→ |
12 |
|
h(13,12) |
→ |
14 |
|
h(14,11) |
→ |
8 |
|
h(14,11) |
→ |
12 |
The automaton is closed under rewriting as it is compatible.