We consider the TRS containing the following rules:
0(1(2(1(x)))) | → | 1(2(1(1(0(1(2(0(1(2(x)))))))))) | (1) |
0(1(2(1(x)))) | → | 1(2(1(1(0(1(2(0(1(2(0(1(2(x))))))))))))) | (2) |
0(1(2(1(x)))) | → | 1(2(1(1(0(1(2(0(1(2(0(1(2(0(1(2(x)))))))))))))))) | (3) |
0(1(2(1(x)))) | → | 1(2(1(1(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(x))))))))))))))))))) | (4) |
0(1(2(1(x)))) | → | 1(2(1(1(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(x)))))))))))))))))))))) | (5) |
0(1(2(1(x)))) | → | 1(2(1(1(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(0(1(2(x))))))))))))))))))))))))) | (6) |
The underlying signature is as follows:
{0/1, 1/1, 2/1}t0 | = | 0(1(2(1(c_1)))) |
→ | 1(2(1(1(0(1(2(0(1(2(0(1(2(c_1))))))))))))) | |
= | t1 |
t0 | = | 0(1(2(1(c_1)))) |
→ | 1(2(1(1(0(1(2(0(1(2(c_1)))))))))) | |
= | t1 |
π(0) | = | [1] |
π(1) | = | [1] |
π(2) | = | 1 |
π(c_1) | = | [] |