The rewrite relation of the following TRS is considered.
c(c(x1)) | → | a(b(x1)) | (1) |
b(x1) | → | a(a(x1)) | (2) |
b(b(b(x1))) | → | a(c(b(x1))) | (3) |
a(c(a(x1))) | → | a(c(c(x1))) | (4) |
c#(c(x1)) | → | a#(b(x1)) | (5) |
c#(c(x1)) | → | b#(x1) | (6) |
b#(x1) | → | a#(a(x1)) | (7) |
b#(x1) | → | a#(x1) | (8) |
b#(b(b(x1))) | → | a#(c(b(x1))) | (9) |
b#(b(b(x1))) | → | c#(b(x1)) | (10) |
a#(c(a(x1))) | → | a#(c(c(x1))) | (11) |
a#(c(a(x1))) | → | c#(c(x1)) | (12) |
a#(c(a(x1))) | → | c#(x1) | (13) |
The dependency pairs are split into 1 component.
c#(c(x1)) | → | b#(x1) | (6) |
b#(x1) | → | a#(x1) | (8) |
a#(c(a(x1))) | → | a#(c(c(x1))) | (11) |
a#(c(a(x1))) | → | c#(c(x1)) | (12) |
a#(c(a(x1))) | → | c#(x1) | (13) |
b#(b(b(x1))) | → | a#(c(b(x1))) | (9) |
[c#(x1)] | = |
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[c(x1)] | = |
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[b#(x1)] | = |
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[a#(x1)] | = |
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[a(x1)] | = |
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[b(x1)] | = |
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b#(x1) | → | a#(x1) | (8) |
[c#(x1)] | = |
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[c(x1)] | = |
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[b#(x1)] | = |
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[a#(x1)] | = |
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[a(x1)] | = |
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[b(x1)] | = |
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b#(b(b(x1))) | → | a#(c(b(x1))) | (9) |
The dependency pairs are split into 1 component.
a#(c(a(x1))) | → | a#(c(c(x1))) | (11) |
[a#(x1)] | = |
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[c(x1)] | = |
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[a(x1)] | = |
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[b(x1)] | = |
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a#(c(a(x1))) | → | a#(c(c(x1))) | (11) |
There are no pairs anymore.