The rewrite relation of the following TRS is considered.
a(x1) | → | x1 | (1) |
a(a(b(x1))) | → | c(b(a(a(x1)))) | (2) |
b(c(x1)) | → | a(b(x1)) | (3) |
a#(a(b(x1))) | → | b#(a(a(x1))) | (4) |
a#(a(b(x1))) | → | a#(a(x1)) | (5) |
a#(a(b(x1))) | → | a#(x1) | (6) |
b#(c(x1)) | → | a#(b(x1)) | (7) |
b#(c(x1)) | → | b#(x1) | (8) |
[a#(x1)] | = | 1 · x1 |
[a(x1)] | = | 1 · x1 |
[b(x1)] | = | 1 + 1 · x1 |
[b#(x1)] | = | 1 + 1 · x1 |
[c(x1)] | = | 1 · x1 |
a#(a(b(x1))) | → | a#(a(x1)) | (5) |
a#(a(b(x1))) | → | a#(x1) | (6) |
[a#(x1)] | = |
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[a(x1)] | = |
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[b(x1)] | = |
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[b#(x1)] | = |
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[c(x1)] | = |
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b#(c(x1)) | → | b#(x1) | (8) |
[a#(x1)] | = |
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[a(x1)] | = |
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[b(x1)] | = |
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[b#(x1)] | = |
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[c(x1)] | = |
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a#(a(b(x1))) | → | b#(a(a(x1))) | (4) |
[b#(x1)] | = | 1 + 1 · x1 |
[c(x1)] | = | 1 · x1 |
[a#(x1)] | = | 0 |
[b(x1)] | = | 0 |
[a(x1)] | = | 1 · x1 |
b#(c(x1)) | → | a#(b(x1)) | (7) |
There are no pairs anymore.