Certification Problem

Input (TPDB SRS_Standard/ICFP_2010/3268)

The rewrite relation of the following TRS is considered.

1(4(x1)) 3(1(1(2(2(4(x1)))))) (1)
5(4(x1)) 4(2(3(1(1(1(x1)))))) (2)
0(3(0(x1))) 2(1(1(0(2(0(x1)))))) (3)
0(5(5(x1))) 1(0(1(3(4(2(x1)))))) (4)
1(5(4(x1))) 0(2(5(2(0(4(x1)))))) (5)
3(5(4(x1))) 4(1(3(4(2(3(x1)))))) (6)
4(1(4(x1))) 3(3(2(2(3(1(x1)))))) (7)
5(4(0(x1))) 2(4(0(4(4(0(x1)))))) (8)
5(4(0(x1))) 5(1(5(2(1(0(x1)))))) (9)
5(4(4(x1))) 4(1(1(3(2(4(x1)))))) (10)
5(5(4(x1))) 3(4(4(1(2(2(x1)))))) (11)
0(5(5(0(x1)))) 0(2(0(0(3(0(x1)))))) (12)
0(5(5(4(x1)))) 0(1(3(4(3(4(x1)))))) (13)
1(4(5(4(x1)))) 0(4(5(0(2(1(x1)))))) (14)
1(4(5(5(x1)))) 0(0(1(3(4(1(x1)))))) (15)
2(5(4(0(x1)))) 0(4(1(2(4(0(x1)))))) (16)
4(3(0(5(x1)))) 3(3(2(3(5(5(x1)))))) (17)
5(4(0(0(x1)))) 1(0(4(0(2(2(x1)))))) (18)
5(4(0(2(x1)))) 3(0(4(5(0(2(x1)))))) (19)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by NaTT @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
5#(4(x1)) 2#(3(1(1(1(x1))))) (20)
1#(4(5(5(x1)))) 3#(4(1(x1))) (21)
4#(1(4(x1))) 2#(3(1(x1))) (22)
0#(5(5(0(x1)))) 0#(2(0(0(3(0(x1)))))) (23)
1#(4(5(4(x1)))) 4#(5(0(2(1(x1))))) (24)
1#(4(5(5(x1)))) 0#(0(1(3(4(1(x1)))))) (25)
2#(5(4(0(x1)))) 4#(1(2(4(0(x1))))) (26)
5#(4(4(x1))) 4#(1(1(3(2(4(x1)))))) (27)
4#(1(4(x1))) 2#(2(3(1(x1)))) (28)
5#(4(0(0(x1)))) 1#(0(4(0(2(2(x1)))))) (29)
4#(1(4(x1))) 3#(2(2(3(1(x1))))) (30)
1#(4(5(4(x1)))) 0#(2(1(x1))) (31)
5#(4(0(0(x1)))) 2#(2(x1)) (32)
5#(4(0(0(x1)))) 4#(0(2(2(x1)))) (33)
0#(5(5(x1))) 1#(3(4(2(x1)))) (34)
0#(3(0(x1))) 2#(0(x1)) (35)
5#(4(4(x1))) 1#(1(3(2(4(x1))))) (36)
1#(5(4(x1))) 5#(2(0(4(x1)))) (37)
0#(3(0(x1))) 1#(0(2(0(x1)))) (38)
5#(4(4(x1))) 1#(3(2(4(x1)))) (39)
1#(4(x1)) 1#(1(2(2(4(x1))))) (40)
1#(4(x1)) 3#(1(1(2(2(4(x1)))))) (41)
4#(3(0(5(x1)))) 2#(3(5(5(x1)))) (42)
5#(4(0(2(x1)))) 3#(0(4(5(0(2(x1)))))) (43)
1#(4(5(4(x1)))) 2#(1(x1)) (44)
5#(4(x1)) 1#(x1) (45)
4#(3(0(5(x1)))) 3#(5(5(x1))) (46)
1#(5(4(x1))) 0#(4(x1)) (47)
2#(5(4(0(x1)))) 1#(2(4(0(x1)))) (48)
4#(1(4(x1))) 3#(3(2(2(3(1(x1)))))) (49)
0#(5(5(x1))) 0#(1(3(4(2(x1))))) (50)
1#(5(4(x1))) 0#(2(5(2(0(4(x1)))))) (51)
0#(5(5(4(x1)))) 0#(1(3(4(3(4(x1)))))) (52)
3#(5(4(x1))) 3#(4(2(3(x1)))) (53)
3#(5(4(x1))) 2#(3(x1)) (54)
5#(4(0(0(x1)))) 0#(2(2(x1))) (55)
4#(3(0(5(x1)))) 3#(2(3(5(5(x1))))) (56)
1#(4(x1)) 1#(2(2(4(x1)))) (57)
0#(5(5(x1))) 2#(x1) (58)
5#(5(4(x1))) 4#(4(1(2(2(x1))))) (59)
0#(3(0(x1))) 1#(1(0(2(0(x1))))) (60)
5#(5(4(x1))) 3#(4(4(1(2(2(x1)))))) (61)
5#(4(0(x1))) 0#(4(4(0(x1)))) (62)
1#(4(x1)) 2#(4(x1)) (63)
4#(1(4(x1))) 1#(x1) (64)
5#(4(0(0(x1)))) 0#(4(0(2(2(x1))))) (65)
0#(3(0(x1))) 2#(1(1(0(2(0(x1)))))) (66)
3#(5(4(x1))) 3#(x1) (67)
0#(5(5(0(x1)))) 0#(0(3(0(x1)))) (68)
5#(4(0(x1))) 2#(4(0(4(4(0(x1)))))) (69)
4#(3(0(5(x1)))) 3#(3(2(3(5(5(x1)))))) (70)
0#(5(5(x1))) 1#(0(1(3(4(2(x1)))))) (71)
5#(4(0(x1))) 4#(4(0(x1))) (72)
0#(5(5(4(x1)))) 1#(3(4(3(4(x1))))) (73)
5#(4(0(2(x1)))) 0#(4(5(0(2(x1))))) (74)
0#(5(5(0(x1)))) 2#(0(0(3(0(x1))))) (75)
1#(5(4(x1))) 2#(5(2(0(4(x1))))) (76)
5#(4(4(x1))) 3#(2(4(x1))) (77)
5#(5(4(x1))) 4#(1(2(2(x1)))) (78)
5#(4(0(x1))) 5#(2(1(0(x1)))) (79)
1#(4(5(5(x1)))) 1#(x1) (80)
3#(5(4(x1))) 4#(1(3(4(2(3(x1)))))) (81)
1#(4(5(4(x1)))) 1#(x1) (82)
3#(5(4(x1))) 4#(2(3(x1))) (83)
0#(5(5(x1))) 3#(4(2(x1))) (84)
0#(5(5(x1))) 4#(2(x1)) (85)
5#(4(0(2(x1)))) 5#(0(2(x1))) (86)
0#(5(5(0(x1)))) 3#(0(x1)) (87)
0#(3(0(x1))) 0#(2(0(x1))) (88)
5#(4(x1)) 1#(1(x1)) (89)
4#(1(4(x1))) 3#(1(x1)) (90)
2#(5(4(0(x1)))) 0#(4(1(2(4(0(x1)))))) (91)
5#(5(4(x1))) 2#(x1) (92)
5#(4(0(x1))) 1#(0(x1)) (93)
1#(4(5(4(x1)))) 0#(4(5(0(2(1(x1)))))) (94)
1#(4(5(5(x1)))) 0#(1(3(4(1(x1))))) (95)
1#(4(5(5(x1)))) 4#(1(x1)) (96)
5#(5(4(x1))) 2#(2(x1)) (97)
4#(3(0(5(x1)))) 5#(5(x1)) (98)
0#(5(5(4(x1)))) 3#(4(x1)) (99)
0#(5(5(0(x1)))) 0#(3(0(x1))) (100)
5#(4(0(x1))) 1#(5(2(1(0(x1))))) (101)
5#(4(0(2(x1)))) 4#(5(0(2(x1)))) (102)
5#(5(4(x1))) 1#(2(2(x1))) (103)
5#(4(0(0(x1)))) 2#(x1) (104)
1#(4(5(5(x1)))) 1#(3(4(1(x1)))) (105)
2#(5(4(0(x1)))) 2#(4(0(x1))) (106)
1#(4(5(4(x1)))) 5#(0(2(1(x1)))) (107)
5#(4(0(x1))) 2#(1(0(x1))) (108)
0#(5(5(4(x1)))) 4#(3(4(x1))) (109)
5#(4(x1)) 3#(1(1(1(x1)))) (110)
1#(4(x1)) 2#(2(4(x1))) (111)
5#(4(x1)) 4#(2(3(1(1(1(x1)))))) (112)
1#(5(4(x1))) 2#(0(4(x1))) (113)
3#(5(4(x1))) 1#(3(4(2(3(x1))))) (114)
0#(5(5(4(x1)))) 3#(4(3(4(x1)))) (115)
5#(4(x1)) 1#(1(1(x1))) (116)
5#(4(0(x1))) 4#(0(4(4(0(x1))))) (117)
5#(4(4(x1))) 2#(4(x1)) (118)
5#(4(0(x1))) 5#(1(5(2(1(0(x1)))))) (119)

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.