The rewrite relation of the following TRS is considered.
| a(a(d(d(x1)))) | → | d(d(b(b(x1)))) | (1) |
| a(a(x1)) | → | b(b(b(b(b(b(x1)))))) | (2) |
| b(b(d(d(b(b(x1)))))) | → | a(a(c(c(x1)))) | (3) |
| c(c(x1)) | → | d(d(x1)) | (4) |
| a#(a(x1)) | → | b#(b(b(b(b(x1))))) | (5) |
| a#(a(x1)) | → | b#(x1) | (6) |
| b#(b(d(d(b(b(x1)))))) | → | c#(c(x1)) | (7) |
| a#(a(d(d(x1)))) | → | b#(b(x1)) | (8) |
| a#(a(d(d(x1)))) | → | b#(x1) | (9) |
| b#(b(d(d(b(b(x1)))))) | → | a#(a(c(c(x1)))) | (10) |
| b#(b(d(d(b(b(x1)))))) | → | c#(x1) | (11) |
| a#(a(x1)) | → | b#(b(x1)) | (12) |
| a#(a(x1)) | → | b#(b(b(b(x1)))) | (13) |
| a#(a(x1)) | → | b#(b(b(b(b(b(x1)))))) | (14) |
| b#(b(d(d(b(b(x1)))))) | → | a#(c(c(x1))) | (15) |
| a#(a(x1)) | → | b#(b(b(x1))) | (16) |
The dependency pairs are split into 1 component.
| a#(a(x1)) | → | b#(b(b(x1))) | (16) |
| a#(a(d(d(x1)))) | → | b#(x1) | (9) |
| b#(b(d(d(b(b(x1)))))) | → | a#(c(c(x1))) | (15) |
| a#(a(x1)) | → | b#(b(b(b(b(b(x1)))))) | (14) |
| a#(a(x1)) | → | b#(b(b(b(x1)))) | (13) |
| a#(a(d(d(x1)))) | → | b#(b(x1)) | (8) |
| a#(a(x1)) | → | b#(x1) | (6) |
| a#(a(x1)) | → | b#(b(x1)) | (12) |
| b#(b(d(d(b(b(x1)))))) | → | a#(a(c(c(x1)))) | (10) |
| a#(a(x1)) | → | b#(b(b(b(b(x1))))) | (5) |
| [a(x1)] | = | 15923 |
| [d(x1)] | = | 1 |
| [b(x1)] | = | 15923 |
| [c(x1)] | = | 1 |
| [c#(x1)] | = | 0 |
| [a#(x1)] | = | x1 + 0 |
| [b#(x1)] | = | 15923 |
| c(c(x1)) | → | d(d(x1)) | (4) |
| a(a(d(d(x1)))) | → | d(d(b(b(x1)))) | (1) |
| b(b(d(d(b(b(x1)))))) | → | a(a(c(c(x1)))) | (3) |
| a(a(x1)) | → | b(b(b(b(b(b(x1)))))) | (2) |
| b#(b(d(d(b(b(x1)))))) | → | a#(c(c(x1))) | (15) |
The dependency pairs are split into 1 component.
| a#(a(d(d(x1)))) | → | b#(x1) | (9) |
| a#(a(d(d(x1)))) | → | b#(b(x1)) | (8) |
| b#(b(d(d(b(b(x1)))))) | → | a#(a(c(c(x1)))) | (10) |
| a#(a(x1)) | → | b#(x1) | (6) |
| a#(a(x1)) | → | b#(b(x1)) | (12) |
| a#(a(x1)) | → | b#(b(b(x1))) | (16) |
| a#(a(x1)) | → | b#(b(b(b(x1)))) | (13) |
| a#(a(x1)) | → | b#(b(b(b(b(x1))))) | (5) |
| a#(a(x1)) | → | b#(b(b(b(b(b(x1)))))) | (14) |
| [a(x1)] | = | x1 + 0 |
| [d(x1)] | = | x1 + 52868 |
| [b(x1)] | = | x1 + 0 |
| [c(x1)] | = | x1 + 52868 |
| [c#(x1)] | = | 0 |
| [a#(x1)] | = | x1 + 0 |
| [b#(x1)] | = | x1 + 0 |
| c(c(x1)) | → | d(d(x1)) | (4) |
| a(a(d(d(x1)))) | → | d(d(b(b(x1)))) | (1) |
| b(b(d(d(b(b(x1)))))) | → | a(a(c(c(x1)))) | (3) |
| a(a(x1)) | → | b(b(b(b(b(b(x1)))))) | (2) |
| a#(a(d(d(x1)))) | → | b#(x1) | (9) |
| a#(a(d(d(x1)))) | → | b#(b(x1)) | (8) |
The dependency pairs are split into 1 component.
| b#(b(d(d(b(b(x1)))))) | → | a#(a(c(c(x1)))) | (10) |
| a#(a(x1)) | → | b#(x1) | (6) |
| a#(a(x1)) | → | b#(b(x1)) | (12) |
| a#(a(x1)) | → | b#(b(b(x1))) | (16) |
| a#(a(x1)) | → | b#(b(b(b(x1)))) | (13) |
| a#(a(x1)) | → | b#(b(b(b(b(x1))))) | (5) |
| a#(a(x1)) | → | b#(b(b(b(b(b(x1)))))) | (14) |
| [a(x1)] | = | x1 + 2241 |
| [d(x1)] | = | 0 |
| [b(x1)] | = | 4482 |
| [c(x1)] | = | 0 |
| [c#(x1)] | = | 0 |
| [a#(x1)] | = | x1 + 2241 |
| [b#(x1)] | = | x1 + 0 |
| c(c(x1)) | → | d(d(x1)) | (4) |
| a(a(d(d(x1)))) | → | d(d(b(b(x1)))) | (1) |
| b(b(d(d(b(b(x1)))))) | → | a(a(c(c(x1)))) | (3) |
| a(a(x1)) | → | b(b(b(b(b(b(x1)))))) | (2) |
| a#(a(x1)) | → | b#(x1) | (6) |
The dependency pairs are split into 1 component.
| b#(b(d(d(b(b(x1)))))) | → | a#(a(c(c(x1)))) | (10) |
| a#(a(x1)) | → | b#(b(x1)) | (12) |
| a#(a(x1)) | → | b#(b(b(x1))) | (16) |
| a#(a(x1)) | → | b#(b(b(b(x1)))) | (13) |
| a#(a(x1)) | → | b#(b(b(b(b(x1))))) | (5) |
| a#(a(x1)) | → | b#(b(b(b(b(b(x1)))))) | (14) |
| [a(x1)] | = |
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| [d(x1)] | = |
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| [b(x1)] | = |
x1 +
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| [c(x1)] | = |
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| [c#(x1)] | = |
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| [a#(x1)] | = |
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| [b#(x1)] | = |
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| c(c(x1)) | → | d(d(x1)) | (4) |
| a(a(d(d(x1)))) | → | d(d(b(b(x1)))) | (1) |
| b(b(d(d(b(b(x1)))))) | → | a(a(c(c(x1)))) | (3) |
| a(a(x1)) | → | b(b(b(b(b(b(x1)))))) | (2) |
| b#(b(d(d(b(b(x1)))))) | → | a#(a(c(c(x1)))) | (10) |
| a#(a(x1)) | → | b#(b(x1)) | (12) |
| a#(a(x1)) | → | b#(b(b(x1))) | (16) |
| a#(a(x1)) | → | b#(b(b(b(x1)))) | (13) |
| a#(a(x1)) | → | b#(b(b(b(b(x1))))) | (5) |
| a#(a(x1)) | → | b#(b(b(b(b(b(x1)))))) | (14) |
The dependency pairs are split into 0 components.